Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Answer:
63 square inches
Step-by-step explanation:
You already have the polgygon divided into two rectangles, so we will use them.
The top rectangle has the dimensions of 5 and 9.
The bottom rectangle has the dimensions of 6 and 3.
To find the area of a rectangle:
area = length x width
A = lw
The area of the top rectangle:
A = 5 x 9
A = 45 square inches
The area of the bottom rectangle:
A = 6 x 3
A = 18 square inches
To find the total area, add the two areas together.
45 + 18 = 63 square inches
