Assuming Jerry calculates that if he makes a deposit of $6 each month at an APR of 4.8%, then at the end of two years the correct balance will be: $158.5
First step is to determine Jerry total deposit
over the two years
Total deposit = 24×$5
Total deposit= $144
Now let determine what the correct balance will be at end of two years
Using this formula
Maximum Amount=Principal (1+r)^t
<em>Where</em>:
Principal=$144
r=4.8%/12 = 0.4% or 0.004
t=24 months
Let plug in the formula
Maximum Balance = $144 (1.004)^24
Maximum Balance = $158.5
Based on the above calculation both Jerry $100 and Benny $163 balance are eliminated or rule out because the correct balance after two years is $158.5
Inconclusion Assuming Jerry calculates that if he makes a deposit of $6 each month at an APR of 4.8%, then at the end of two years the correct balance will be: $158.5
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Y=-2x+0 haahahaha hope i helped i think
First, do 0.4 + 0.4. So, you can see what number you should get when you check your answer. For this, you should get 0.8
Then, do 0.8 + 1.6
After you add those 0.8 and 1.6, you should get your answer.
To check your answer, plug in your answer where B is and see if you get 0.8. I hope this helps! I did as much explaining as I could! If you need anymore help with this, just comment
Answer:
1. ![(\sqrt[5]{(m+2)})^{3} = (m+2)^{\frac{3}{5}}](https://tex.z-dn.net/?f=%28%5Csqrt%5B5%5D%7B%28m%2B2%29%7D%29%5E%7B3%7D%20%3D%20%20%28m%2B2%29%5E%7B%5Cfrac%7B3%7D%7B5%7D%7D)
2. ![(\sqrt[3]{(m+2)})^{5} = (m+2)^{\frac{5}{3}}](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B%28m%2B2%29%7D%29%5E%7B5%7D%20%3D%20%20%28m%2B2%29%5E%7B%5Cfrac%7B5%7D%7B3%7D%7D)
3. ![\sqrt[5]{(m)}^{3}+2 = m^{\frac{3}{5}}+2](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B%28m%29%7D%5E%7B3%7D%2B2%20%3D%20%20m%5E%7B%5Cfrac%7B3%7D%7B5%7D%7D%2B2)
4. ![\sqrt[3]{(m)}^{5}+2 = m^{\frac{5}{3}}+2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%28m%29%7D%5E%7B5%7D%2B2%20%3D%20%20m%5E%7B%5Cfrac%7B5%7D%7B3%7D%7D%2B2)
Step-by-step explanation:
Recall that
![(\sqrt[n]{x})^{m} = (x^{\frac{m}{n}})](https://tex.z-dn.net/?f=%28%5Csqrt%5Bn%5D%7Bx%7D%29%5E%7Bm%7D%20%3D%20%20%28x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%29)
Where 
is called radicand and n is called index
1. Root(5, (m + 2) ^ 3)
In this case,
n is 5
m is 3
x = (m + 2)
2. Root(3, (m + 2) ^ 5)
In this case,
n is 3
m is 5
x = (m + 2)
3. Root(5, m ^ 3) + 2
In this case,
n is 5
m is 3
x = m
4. Root(3, m ^ 5) + 2
In this case,
n is 3
m is 5
x = m
