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Cerrena [4.2K]
2 years ago
6

Please help me I'm so confused

Mathematics
1 answer:
jenyasd209 [6]2 years ago
6 0
First, in order to know the surface area, you need to know the length and width as well, not just the hight.
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Alja [10]

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I can't understand what you have written and what to find

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Tim has 72 football cards and ben has 33 football cards. How many more football cards does tim have?
ankoles [38]

Answer:

the answer is 39


Step-by-step explanation:

you have to just easily subtract 72-33= 39


BRAINIEST PLZZZZ AND RATE ME

4 0
3 years ago
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20 POINTS AND BRAINLIEST !! PLEASE ANSWER THIS QUESTION !!
BlackZzzverrR [31]

Answer:

-14

Step-by-step explanation:

f(x) = 3x-5

g(x) = -x^2 +1

g(2) = - (2^2) +1

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2 years ago
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A plane flying horizontally at an altitude of 3 miles and a speed of 500 mi/h passes directly over a radar station. Find the rat
konstantin123 [22]

Answer:

The rate at which the distance from the plane to the station is increasing is 331 miles per hour.

Step-by-step explanation:

We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:

a: is one side of the triangle = altitude of the plane = 3 miles

b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles

h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles                    

First, we need to find b:    

a^{2} + b^{2} = h^{2}   (1)    

b = \sqrt{h^{2} - a^{2}} = \sqrt{(4 mi)^{2} - (3 mi)^{2}} = \sqrt{7} miles

Now, to find the rate we need to find the derivative of equation (1) with respect to time:

\frac{d}{dt}(a^{2}) + \frac{d}{dt}(b^{2}) = \frac{d}{dt}(h^{2})

2a\frac{da}{dt} + 2b\frac{db}{dt} = 2h\frac{dh}{dt}

Since "da/dt" is constant (the altitude of the plane does not change with time), we have:  

0 + 2b\frac{db}{dt} = 2h\frac{dh}{dt}

And knowing that the plane is moving at a speed of 500 mi/h (db/dt):

\sqrt{7} mi*500 mi/h = 4 mi*\frac{dh}{dt}

\frac{dh}{dt} = \frac{\sqrt{7} mi*500 mi/h}{4 mi} = 331 mi/h  

Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.

I hope it helps you!

4 0
2 years ago
What the percent change from 50; 35
il63 [147K]
50 -> 35=change by 15
change by 5=10%
so multiply by 3 
3(5)=3(10%)
15=30%
5 0
3 years ago
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