A student calculates that the circumference of a tire with a rim diameter of 15 inches and a sidewall width of 4.6 inches is 61.
8 inches by doing the following calculation:(15+4.6)xpi. Explain the error. (Show problem set up. Provide appropriate units)
1 answer:
Answer:
The error was on the diameter. The tire diameter was supposed to be;
4.6+15+4.6=24.2
The student only includes one sidewall width
Step-by-step explanation:
The question is on circumerence of a tire
Here we apply the formulae for circumference of a circle
C=2 ×r or
× d where r is the radius of the tire and d is the diameter
Finding d= diameter of rim + sidewall to the right +sidewall to the left
d= 15+4.6+4.6=24.2 inches
r=d/2= 12.1
C=2 ××r
C=2×3.14×12.1 =75.99 Inches
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We have building B was built two years before building C.
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