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2 years ago

5

Which picture shows the inverse, f −1, of the function shown?

1 answer:

LekaFEV [45]2 years ago

6 0

Answer:

(d) Inverse of f. Domain: 6, 9, 3. Range: 8, 10, 12. 6 goes to 8; 9 goes to 10; 3 goes to 12.

Step-by-step explanation:

Apparently function f is defined by the ordered pairs (8, 6), (10, 9), (12, 3).

The inverse function will be defined by the ordered pairs with the input and output reversed:

(6, 8), (10, 9), (3, 12)

This seems to be described by the last answer choice.

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I need help!!! and make sure its 100 percent right!! my graduation is at rate of not passing

geniusboy [140]

Answer:

I'm not 100% sure I'm right but I think x = -1

because it says "f(x)" and then it says"Find f(-1)" so that is why I think x = -1

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2 years ago

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Bryce tried to solve an equation step by step.

Aloiza [94]

$$c=\frac{1}{3}$

Solution:

Given equation is $\frac{8}{3}=3c+\frac{5}{3}$ .

To solve the equation by step by step.

Step 1: Given

$\frac{8}{3}=3c+\frac{5}{3}$

Step 2: Combine like terms together.

Plus symbol changed to minus when the term goes from right to left (or) left to right of the equal sign.

$\frac{8}{3}-\frac{5}{3}=3c$

Step 3: Subtract the fractions in the left side.

$\frac{3}{3}=3c$

⇒ $1=3c$$

Step 4: Divide both side of the equation by 3, we get

$\frac{1}{3} =\frac{3c}{3}$

$\frac{1}{3} =c$

Hence, the answer is $c=\frac{1}{3}$ .

8 0

3 years ago

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Sally and Eddy had a total of $580 after spending $80 and eddy had 240 left how much money does Sally have?

levacccp [35]

Answer:

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Step-by-step explanation:

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2 years ago

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

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2 years ago

Clasifica los siguientes números en los conjuntos numéricos a los que pertenezcan. Si es posible

Natasha_Volkova [10]

<h2>Please write ur question properly</h2>

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2 years ago