Answer:
√(6ax)
Explanation:
Hi!
The question states that during a time t the motorcyle underwent a displacement x at constant acceleration a starting from rest, mathematically we can express it as:
x=(1/2)at^2
Then the we need to find the time t' for which the displacement is 3x
3x=(1/2)a(t')^2
Solving for t':
t'=√(6x/a)
Now, the velocity of the motorcycle as a function of time is:
v(t)=a*t
Evaluating at t=t'
v(t')=a*√(6x/a)=√(6*x*a)
Which is the final velocity
Have a nice day!
Answer:
Super-critical mass
Explanation:
This term refers to the mass, in which the amount of fission processes per unit of time increases to the point, where some intrinsic feedback mechanism causes the reactor to reach an equilibrium point at a high temperature or power, that is, It becomes critical again, or it is destroyed due to the amount of processes.
do not forget to change grams to kilograms and if it were in centimeters convert them to meters.
Answer:
A)
B)
C)
Explanation:
Given that a pendulum is suspended by a shaft with a very light thin rod.
Followed by the given information: m = 100 g, I = 0.5 m, g = 9.8 m / s²
We can determine the answer to these questions using angular kinematics.
Angular kinematics is just derived from linear kinematics but in different symbols, and expressions.
Here are the formulas for angular kinematics:
- θ = ωt
- ∆w =
- L [Angular momentum] = mvr [mass × velocity × radius]
A) What is the minimum speed required for the pendulum to traverse the complete circle?
We can use the formula v = √gL derived from
B) The same question if the pendulum is suspended with a wire?
C) What is the ratio of the two calculated speeds?
