If one of the four engines suddenly fail, so this means
that we only get 3 / 4 of the original force. Since force is the product of
mass and acceleration and mass is constant, therefore we get 3 / 4 of the
original acceleration.
So the remaining acceleration is:
a = (2.0 m/s^2) * (3 / 4)
<span>a = 1.5 m/s^2</span>
When travelling on a two lane highway driving 50 to 55 mph, you need a 10-12 second gap in oncoming traffic to pass safety. At 55 mph, you will travel over 800 feet in 10-12 seconds so will an oncoming vehicle. That means you need over 1600 feet which is about 1/3 of a mile to pass safety. It is harder to see and judge the speed of oncoming vehicles that are traveling 1/3 of a mile or more away from you.
The magnitude of a point charge is 0.189 x 10⁻⁹C.
<h3>Steps</h3>
We have stated that the point charge's electric field is E=2.5 N/C.
Distance from point charge R = 51 cm = 0.51 m
We are aware that the electric field resulting from a point charge is given as E = 1 / 4π∈₀ × Q / R²
so 2.5 = 9 x 10⁹ Q/ 0.68²
The magnitude of a point charge is 0.189 x 10⁻⁹C.
The electric force per unit charge is referred to as the electric field. It is assumed that the field's direction corresponds to the force it would apply to a positive test charge.
From a positive point charge, the electric field radiates outward, and from a negative point charge, it radiates in.
learn more about electric field here
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The potential energy would be greatest at the highest point of the jump; the kinetic energy equaling 0.
Answer: 4850N
Explanation:
Mass of car = 970 kg
Time = 5 s
Speed = 25 m/s
Average force exerted on the car = ?
Recall that Force is the product of the mass of an object and the acceleration by which it moves
i.e Force = mass x acceleration
(Since, acceleration is the rate of change of velocity or speed per unit time)
i.e Acceleration = Speed / Time
Acc = 25m/s / 5s
Acc = 5m/s^2
Average force = mass x acceleration
Avg force = 970 kg x 5m/s^2
= 4850N
Thus, the average force exerted on the car is 4850 Newton
