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3 years ago

What does the power of a machine measure?

Physics

2 answers:

GarryVolchara [31]3 years ago

5 0

The power of a machine is the work/time ratio for that particular machine

Its the rate of doing work.

bixtya [17]3 years ago

4 0

The power of a machine is the work/time ratio for that particular machine.

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Select ALL of the following statements that provide evidence that there is friction acting on a cart moving along a level track.

Sati [7]

Answer:

1st and 4th one................

6 0

3 years ago

A chain saw produces a spherical sound wave having a frequency of 214Hz in air at 358C (308.2K or 958F). At a distance of 600mm

Helen [10]

Given Information:

Frequency = 214 Hz

Temperature = 358° C = 308.2 K

Sound Pressure = p = 100 dB = 2 pascal

Distance = 600 mm = 0.60 m

Required Information:

(a) Acoustic Power Level = ?

(b) Acoustic Particle Velocity = ?

and Velocity level at a distance of 600 mm = ?

Answer:

Acoustic Power Level = Lw = 106.44 dB

Acoustic Particle Velocity = v = 0.0106 m/s

Velocity level = 60.25 dB

Explanation:

(a) Acoustic Power Level

Acoustic Power = W = 4πr² I

Acoustic Intensity = I = p ²/Z₀

Where Z₀ is the characteristic impedance of air Z₀ = 409.8 rayl

I = p ²/Z₀ = (2)²/409.8 = 0.00976 W/m²

W = 4πr² I = 4*π(0.60)²*0.00976 = 0.0441 W

Acoustic Power Level = Lw = 10log(W/Wref)

Where Wref is Reference Acoustic Power Wref = 1x10⁻¹² W

Lw = 10log(W/Wref) = 10log(0.0441/1x10⁻¹²) = 106.44 dB

Lw = 106.44 dB

(b) Acoustic Particle Velocity

Acoustic Particle velocity = v = p ²/Zs

Where Zs is specific acoustic impedance

Zs = Z₀kr/(1 + k²r²)⁰°⁵

Where k = 2πf/c and c = 346.1 m/s is the speed of sound in air

k = 2π*214/346.1 = 3.885 per m

Zs = 409.8*3.885*0.60/(1 + (3.885)²(0.60)²)⁰°⁵

Zs = 376.6 rayl

v = p ²/Zs = 2²/376.6 = 0.0106 m/s

v = 0.0106 m/s

Velocity level = 10log(v/vref) where vref = 10x10⁻⁹ m/s

Velocity level = 10log(0.0106/10x10⁻⁹) = 60.25 dB

Velocity level = 60.25 dB

8 0

4 years ago

A small object carrying a charge of -4.00 nC is acted upon by a downward force of 19.0 nN when placed at a certain point in an e

Gala2k [10]

Explanation:

Given that,

Charge acting on the object, $q=-4\ nC=-4\times 10^{-9}\ C$

Force acting on the object, $F=19\ nC=19\times 10^{-9}\ C$ (in downward direction)

(a) The electric force acting in the electric field is given by :

$F=qE$

E is the electric field

$E=\dfrac{F}{q}$

$E=\dfrac{19\times 10^{-9}\ N}{4\times 10^{-9}\ C}$

E = 4.75 N/C

The direction of electric field is as same as electric force. But it is negative charge. So, the direction of electric field is in upward direction.

(b) The charge on the proton is, $q=1.6\times 10^{-19}\ C$

The force acting on the proton is :

$F=qE$

$F=1.6\times 10^{-19}\times 4.75$

$F=7.6\times 10^{-19}\ N$

If the charge on the proton is positive, the force on the proton is in upward direction.

Hence, this is the required solution.

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3 years ago

Describe the difference between a soil horizon and a soil proﬁle

mario62 [17]

Soil profile includes all the sections/ horizons of the vertical soil depth from top to bottom including the transitions from one horizon to another. A soil horizon is a distinct layer/section of soil with more or less the same texture. Therefore, a soil profile is made of soil horizons.

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