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bezimeni [28]
3 years ago
6

¿Qué sucede con la Energía interna de un sistema cuando sobre él se efectúa trabajo? ¿Qué ocurre con su temperatura?

Physics
1 answer:
disa [49]3 years ago
5 0

Answer:

Disminuye la energía y la temperatura internas.

Explanation:

translation:

it decreases the internal energy and temperature

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marissa [1.9K]
Its most likely C. Remember the bigger the vehicle the bigger the area it needs to make a safe turn.
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3 years ago
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Which form of energy is responsible for the change of state here?
liq [111]

Answer:

d

Explanation:

8 0
3 years ago
A 10-g bullet moving horizontally with a speed of 1.8 km/s strikes and passes through a 5.0-kg block initially at rest on a hori
UNO [17]

Answer:

6.4 J

Explanation:

m = mass of the bullet = 10 g = 0.010 kg

v = initial velocity of bullet before collision = 1.8 km/s = 1800 m/s

v'  = final velocity of the bullet after collision = 1 km/s = 1000 m/s

M = mass of the block = 5 kg

V = initial velocity of block before collision = 0 m/s

V'  = final velocity of the block after collision = ?

Using conservation of momentum

mv + MV = mv' + MV'

(0.010) (1800) + (5) (0) = (0.010) (1000) + (5) V'

V' = 1.6 m/s

Kinetic energy of the block after the collision is given as

KE = (0.5) M V'²

KE = (0.5) (5) (1.6)²

KE = 6.4 J

4 0
4 years ago
Which symbol represents a type of electromagnetic radiation released during radioactive decay?
Lena [83]
The correct option is (D) Gamma ( _0^0\gamma )

Explanation:
Now this question is a tricky one because all of these options are somehow involved in radioactive decay; however, in this case the SYMBOL is required NOT the elements. There are three symbols involved in radioactive decay, which are:
1. α for alpha decay
2. β for beta decay
3. γ for gamma decay 

In the options only one symbol is present which is gamma. Hence option (D) Gamma ( _0^0\gamma ) is the correct answer.

-i
4 0
4 years ago
Notice that the speed halfway down is not half the final speed. Another interesting point is that the final answer doesn't depen
ValentinkaMS [17]

Answer:

its speed is insignificant before the diver's speed change, so the result does not change

Explanation:

In this exercise of conservation of the momentum, the system is formed by the diver and the Earth

initial instant (before jumping)

       p₀ = 0

final instant (after jumping)

      p_{f} = m v + M v²

how momentum is conserved

        p₀ = p_{f}

        0 = m v + M v²

         v² = m / M v

since the mass of the Earth is M = 10²⁴ kg

   its speed is insignificant before the diver's speed change, so the result does not change

7 0
3 years ago
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