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d1i1m1o1n [39]
1 year ago
12

A Spanish test has 30 questions. A student answers 80% correctly.

Mathematics
1 answer:
ad-work [718]1 year ago
6 0

Answer:

24

Step-by-step explanation:

Lets start by working out 80% of 30

80% x 30=24

so the student answered 24 questions correctly

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Choose the correct equation in point slope form for the line that passes through the point with the given slope.
Airida [17]
Here you should use the equation y - y1 = m(x - x1), where (x1, y1) are a point and m is the slope:
y - 1 = -3(x - 2)

I'm not sure if perhaps there's an error in the question or the re-typing but none of the answers stated above match the solution.
8 0
3 years ago
0.5 (x-3) = 3x - 2.5 how many solutions
Nimfa-mama [501]

Answer:

There is 1 solution.

Step-by-step explanation:

0.5(x - 3) = 3x - 2.5

0.5x - 1.5 = 3x - 2.5

-2.5x = -1

x = 0.4

There is 1 solution.

4 0
3 years ago
What is 10/3 divided by 2/3
Amiraneli [1.4K]

Answer:5

Step-by-step explanation:

3 0
2 years ago
A kayaker travels x miles per hour downstream for 4 hours. On the 6-hour return trip, the kayaker travels 2 mile per hour slower
Stolb23 [73]

                              time       *      rate          =       distance

Downstream           4           *       x              =          4(x)

Upstream                6           *     x - 2           =        6(x - 2)

distance downstream = distance upstream:

                              4(x) = 6(x - 2)

                               4x  = 6x - 12

                              -2x  =   -12

                                 x   =    6

Distance Upstream: 4x   = 4(6)   = 24

Distance Upstream: 6(x - 2)  = 6(6 - 2)   = 6(4)   = 24

Total distance traveled is Upstream + Downstream = 24 + 24 = 48

Answer: 48 miles

5 0
3 years ago
Prove for any positive integer n, n^3 +11n is a multiple of 6
suter [353]

There are probably other ways to approach this, but I'll focus on a proof by induction.

The base case is that n = 1. Plugging this into the expression gets us

n^3+11n = 1^3+11(1) = 1+11 = 12

which is a multiple of 6. So that takes care of the base case.

----------------------------------

Now for the inductive step, which is often a tricky thing to grasp if you're not used to it. I recommend keeping at practice to get better familiar with these types of proofs.

The idea is this: assume that k^3+11k is a multiple of 6 for some integer k > 1

Based on that assumption, we need to prove that (k+1)^3+11(k+1) is also a multiple of 6. Note how I've replaced every k with k+1. This is the next value up after k.

If we can show that the (k+1)th case works, based on the assumption, then we've effectively wrapped up the inductive proof. Think of it like a chain of dominoes. One knocks over the other to take care of every case (aka every positive integer n)

-----------------------------------

Let's do a bit of algebra to say

(k+1)^3+11(k+1)

(k^3+3k^2+3k+1) + 11(k+1)

k^3+3k^2+3k+1+11k+11

(k^3+11k) + (3k^2+3k+12)

(k^3+11k) + 3(k^2+k+4)

At this point, we have the k^3+11k as the first group while we have 3(k^2+k+4) as the second group. We already know that k^3+11k is a multiple of 6, so we don't need to worry about it. We just need to show that 3(k^2+k+4) is also a multiple of 6. This means we need to show k^2+k+4 is a multiple of 2, i.e. it's even.

------------------------------------

If k is even, then k = 2m for some integer m

That means k^2+k+4 = (2m)^2+(2m)+4 = 4m^2+2m+4 = 2(m^2+m+2)

We can see that if k is even, then k^2+k+4 is also even.

If k is odd, then k = 2m+1 and

k^2+k+4 = (2m+1)^2+(2m+1)+4 = 4m^2+4m+1+2m+1+4 = 2(2m^2+3m+3)

That shows k^2+k+4 is even when k is odd.

-------------------------------------

In short, the last section shows that k^2+k+4 is always even for any integer

That then points to 3(k^2+k+4) being a multiple of 6

Which then further points to (k^3+11k) + 3(k^2+k+4) being a multiple of 6

It's a lot of work, but we've shown that (k+1)^3+11(k+1) is a multiple of 6 based on the assumption that k^3+11k is a multiple of 6.

This concludes the inductive step and overall the proof is done by this point.

6 0
3 years ago
Read 2 more answers
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