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Leokris [45]
1 year ago
11

Find an expression for the number in the nth term pattern of the sequence. 4 , 7 , 12, 19

Mathematics
1 answer:
EastWind [94]1 year ago
7 0

Answer:

n^2 + 3.

Step-by-step explanation:

4 7 12 19

Differences are 3 5 7   so this a quadratic sequence.

2nd difference = 2 2

So the first part of the expression is n^2

Terms:  4  7  12  19

n^2       1    4   9  16

Difference = 3 3 3 3 3

So the answer is n^2 + 3.

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I believe it would C.
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3 years ago
What is the image of (-4,-4) after a dilation by a scale factor of 3 centered at the<br> origin?
gtnhenbr [62]

Answer:

(-12, -12)

Step-by-step explanation:

Since the scale factor is 3, you would multiply the x-coordinate and y-coordinate by it.

-4×3=-12

Hope this helps!!

3 0
2 years ago
????????????????????/?????????????????????????ching chong
Kitty [74]

Answer:

I think ---- Independent

6 0
3 years ago
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A study of the amount of time it takes a mechanic to rebuild the transmission for a 1992 Chevrolet Cavalier shows that the mean
Dovator [93]

Answer:

B) 0.0069

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 8.4, \sigma = 1.8, n = 40, s = \frac{1.8}{\sqrt{40}} = 0.2846

Find the probability that their mean rebuild time exceeds 9.1 hours.

This is 1 subtracted by the pvalue of Z when X = 9.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{9.1 - 8.4}{0.2846}

Z = 2.46

Z = 2.46 has a pvalue of 0.9931

1 - 0.9931 = 0.0069

So the answer is B.

6 0
3 years ago
Which description below the equation <br> X/4=55
Mariana [72]

x/4 = 55

=> x = 55 × 4

=> x = 220

4 0
2 years ago
Read 2 more answers
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