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egoroff_w [7]
3 years ago
12

Find an equation for the line with the given properties. Perpendicular to the line x - 6y = 8; containing the point (4,4) O 1) y

= 6x - 28 2) y = - (1/6) > - (14/3) 3) y = - 6x + 28 4) y = - 6x - 28
Mathematics
1 answer:
Pepsi [2]3 years ago
8 0

Answer:

Option 3 - y=-6x+28

Step-by-step explanation:

Given : Perpendicular to the line x - 6y = 8; containing the point (4,4).

To Find : An equation for the line with the given properties ?

Solution :

We know that,

When two lines are perpendicular then slope of one equation is negative reciprocal of another equation.

Slope of the equation x - 6y = 8

Converting into slope form y=mx+c,

Where m is the slope.

y=\frac{x-8}{6}

y=\frac{x}{6}-\frac{8}{6}

The slope of the equation is m=\frac{1}{6}

The slope of the perpendicular equation is m_1=-\frac{1}{m}

The required slope is m_1=-\frac{1}{\frac{1}{6}}

m_1=-6

The required equation is y=-6x+c

Substitute point (x,y)=(4,4)

4=-6(4)+c

4=-24+c

c=28

Substitute back in equation,

y=-6x+28

Therefore, The required equation for the line is y=-6x+28

So, Option 3 is correct.

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Answer:

Suppose we have a random number A.

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Which polynomial can be simplified to a difference of squares
Mrrafil [7]
<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

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<h2>Why?</h2>

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Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}

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