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Nikitich [7]
2 years ago
9

Select all the expressions that are equivalent to the polynomial below.

Mathematics
2 answers:
jekas [21]2 years ago
8 0
The answer to this question is D. or C.
jolli1 [7]2 years ago
3 0

Answer:

Options A,C and D

Step-by-step explanation:

(4x+5)(-3x-1) = -12x²-19x-5

Option A:

    (-16x² + 10x - 3) + (4x² - 29x - 2) = -12x²-19x-5

    Option A is correct.

Option B:

    3(x - 5) - 2(6x² + 9x + 5) = -12x²-15x-25

    Option B is wrong.

Option C:

    2(x - 1) - 3(4x² + 7x + 1) = -12x²-19x-5

    Option C is correct.

Option D:

    (2x² - 11x - 9) - (14x² + 8x - 4) = -12x²-19x-5

    Option D is correct.

Option E:

    (-15x² + 9x - 10) + (3x² - 10x - 5) = -12x²-x-15

    Option E is wrong.

Option F:

    (4x² - 13x - 7) - (16x² + 9x - 5) = -12x²-22x-2

    Option F is wrong.

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atroni [7]

the answer is 8^(-3)

4 0
3 years ago
ANSWER QUICKLY PLZ :)​
AfilCa [17]
The answer is (-1,1)
The solution is the point where the two lines cross each other
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5 0
3 years ago
-8(7 + x) = 137<br> What can be used to solve this problem
alexgriva [62]

Answer:

-24.5

Step-by-step explanation:

-56+-8x=137

-8x=196

x=-24.5

3 0
3 years ago
A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar
ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let \mu = <u><em>mean waiting time for bus number 14.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 10 minutes      {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, H_A : \mu < 10 minutes    {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 7.8 minutes

             s = sample standard deviation = 2.5 minutes

             n = sample of different occasions = 18

So, <u><em>test statistics</em></u> =  \frac{7.8-10}{\frac{2.5}{\sqrt{18} } }  ~ t_1_7

                              =  -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0
3 years ago
Given the linear correlation coefficient r and the sample size n, determine the critical values of r and use your
Mila [183]

The critical value of r is mathematically given as r = +0.487, with no significant linear correlation. Option A.

<h3>What are the critical values of r?</h3>

Question Parameters

r = -0.868

n = 5

df = 5 - 2

df = 3

\alpha / 2 =0.025

Critical values r= \pm 0.878

Generally, there exists no linear correlation between the Critical values

as r=0.878

In conclusion,  Critical values: r = +0.487, no significant linear correlation

Read more about Critical values

brainly.com/question/14508634

#SPJ1

5 0
1 year ago
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