Answer:
Let t be temperature
t - 3 < 26
Step-by-step explanation:
Answer:
I think that the equation would be Y= -2X^2-4X-4 .
Step-by-step explanation:
Hope it wad helpful :)
The scale factor of dilation from AB to EF is 0.25
<h3>How to determine the scale factor of dilation?</h3>
The given parameters are:
- EFJL is dilation of ABIK
- AB has a length of 12
- EF has a length of 3
From the above parameters, side lengths AB and EF are corresponding sides
This means that:
The scale factor of dilation (k) is
k = AB/EF
So, we have
k = 3/12
Evaluate
k = 0.25
Hence, the scale factor of dilation from AB to EF is 0.25
Read more about scale factors at:
brainly.com/question/15891755
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7cos(x) + 1 = 6sec(x)
7cos(x) + 1 = 6/cos(x)
7cos^(x) + cos(x) = 6
7cos^(x) + cos(x) - 6 = 0
[7cos(x) - 6][cos(x) + 1] = 0
cos(x) = 6/7 , x = arccos(6/7) and
cos(x) = -1, x = 180
Answer:
√2(√3 - 1)/4
Step-by-step explanation:
To find an exact value for Cos75°, we use the compound angle formula. Since 75° = 45° + 30°, Cos75° = Cos(45° + 30°).
Using Cos(A + B) = CosACosB - SinASinB where A = 45° and B = 30°,
Cos75° = Cos(45° + 30°) = Cos45°Cos30° - Sin45°Sin30°
Now Cos45° = Sin45° = 1/√2 = √2/2, Cos30° = √3/2 and Sin30° = 1/2.
Substituting these values into the above equation, we have
Cos75° = Cos(45° + 30°)
= Cos45°Cos30° - Sin45°Sin30°
= √2/2 × √3/2 - √2/2 × 1/2
= √6/4 -√2/4
= √2(√3 - 1)/4
