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Anna71 [15]
4 years ago
9

What is the exact distance from (-1,4) to (6,-2)? in units​

Mathematics
1 answer:
maxonik [38]4 years ago
8 0

Answer:

\sqrt{85}

Step-by-step explanation:

To calculate the distance (d) use the distance formula

d = √ (x₂ - x₁ )² + ( y₂ - y₁ )²

with (x₁, y₁ ) = (- 1, 4) and (x₂, y₂ ) = (6, - 2)

d = \sqrt{(6+1)^2+(-2-4)^2}

  = \sqrt{7^2+(-6)^2}

  = \sqrt{49+36} = \sqrt{85} ← exact distance

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1st term - 10
2nd term - 10 - 3 = 7
3rd term  - 7 - 3 = 4
4th term - 4 - 3 = 1
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6th term - -2 - 3 = -5
7th term - -5 - 3 = -8 
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Q2) 
<span>the sequence whose nth term is the sum of the first n positive integers
In this we get the term by adding all the integers of the terms before that term 
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6th - 15 + 6 = 21
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10th -  45 + 10 = 55
this is a triangular number pattern
this number pattern can be found out using ; n = (n x (n+1))/2

sequence is - 1,3,6,10,15,21,28,36,45,55

Q3)
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to find 1st term , n = 1
substituting n = 1 in the general term 
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2nd - 3x2- 2x2 = 6 - 4 = 2
3rd - 3x3 - 2x3 = 9-6 = 3
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5th - 3x5 - 2x5 = 15 - 10 = 5
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sequence is 1,2,3,4,5,6,7,8,9,10

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<span>the sequence whose nth term is √ n
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