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2 years ago

PLEASE HELP!!! If f(x) = -2x^2 + x - 5, what is f(3)?

Mathematics

2 answers:

kow [346]2 years ago

4 0

Answer:

f(3) = -10

Step-by-step explanation:

Given

f(x) = -2x² + x - 5

Solving

To find f(3), substitute x = 3 in the function
⇒ f(3) = -2(3)² + (3) + 5
⇒ f(3) = -2(9) + 8
⇒ f(3) = -18 + 8
⇒ f(3) = -10

Vesna [10]2 years ago

3 0

Answer:

f(3) = 6

Step-by-step explanation:

f(x)=2x^2 + x -5

f(3) = 2 (3)^2 + (3) - 5

f(3) = 8 + 3 - 5

f(3) = 11-5

f(3) = 6

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$\huge \mathbb{\green{\fbox{\pink{ANSWER}}}}$

$\\ \: \: \implies \: sin^{4} \: \theta + cos^{4} \: \theta \rightarrow \blue{ \frac{1}{2} }$

$\\ \\ \: \large \mathfrak \green{Solution} :$

$\\ \bf \: Given :$

$\\ \sf \: \: \bf sin \: \theta - cos \: \theta = 0$

$\\ \sf \rightarrow \: sin \: \theta = cos \: \theta$

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$\\ \sf \rightarrow \: tan \: \theta = 1$

$\\ \sf \rightarrow \: tan \: \theta = tan \: 45 \degree$

$\\ \sf \rightarrow \: \theta = 45 \degree$

$\\ \\ \therefore \: sin^{4} \: \theta + cos^{4} \: \theta$

$\\ \sf \rightarrow \: sin^{4} \: 45 \degree + cos^{4} \: 45 \degree$

$\\ \\\sf \rightarrow \: (\frac{1}{ \sqrt{2} } ) ^{4} +(\frac{1}{ \sqrt{2} } ) ^{4}$

$\\ \sf \rightarrow \: ( \frac{1}{ \cancel {\sqrt{2} }} )^{ \cancel{2}} ( \frac{1}{ \cancel{ \sqrt{2} }} )^{\cancel{2}} + ( \frac{1}{ \cancel {\sqrt{2} }} )^{ \cancel{2}} ( \frac{1}{ \cancel{ \sqrt{2} }} )^{\cancel{2}}$

$\\ \\\sf \rightarrow \: \frac{1}{2} × \frac{1}{2} + \frac{1}{2}× \frac{1}{2}$

$\\ \\ \sf \rightarrow \: \frac{1}{4} + \frac{1}{4}$

$\\ \\ \sf \rightarrow \: {\cancel \frac{2} {4}}$

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