Suppose a pound of peanuts is priced at X, M&M is Y, and the equation is 6X+4Y=42.70 8X+5Y=55.27. [8X+5Y=55.27]*4-[6X+4Y=42.70]*5 is [32X+20Y=221.08] - [30X+20Y=213.5] X=3.79 Y=4.99
Remark
This is a very interesting question. Draw a line from the origin to where the upper right vertex of the square touches the line. That line has the property that the its equation is y = x. So the "solution" to the point of intersection is the solution of the two equations.
y = x (1)
3x + 4y = 12 (2)
Put x in for y in equation 2
3x + 4x = 12
7x = 12
x = 12/7
x = 1.714
y = 1.714
Problem A
<em><u>x intercept</u></em>
The x intercept occurs when y = 0
3x + 4(0) = 12
3x = 12 Divide by 3
x = 12/3
x = 4
the x intercept = (4,0)
<em><u>y intercept</u></em>
The y intercept occurs when x =0
3(0) + 4y = 12
4y = 12
y = 12/4
y = 3
y intercept = (0,3)
Problem B
x and y both equal 1.714 so they are also the length of the square's side.
Problem C
See solution above. x =y is the key fact.
x = y = 1.714
I think it’s 135
12x15=180
180 divided by 4/3 or 1 1/3 = 135
Answer:
101 is your answer
Step-by-step explanation:
Remember to follow PEMDAS & the left->right rule.
First, multiply 12 with 13:
12 x 13 = 156
Next, divide 156 with 2
156/2 = 78
Finally, add 23
78 + 23 = 101
101 is your answer
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