Question

Write the equation of a line that is parallel to y=0.6x+3 and that passes through point (-3,-5).​

Answer 1

Answer:

$y = 0.6x - 3.2$

Step-by-step explanation:

To find the line that is parallel, the slopes must be equal.

We have to use the point-slope formula for this problem.

Use the point-slope formula $y = y_{1} = m (x - x_{1})$.

Now, we have to plug in the values of each variable.

$m = 0.6, x_{1} = -3, and - y_{1} = -5$

$y - (-5) = (0.6) (x - (-3))$

Now, we will solve for the last variable, y.

$y = 0.6x - 3.2$

Because $y - (-5) = (0.6) (x - (-3)),$, $y = 0.6x - 3.2$

Carry On Learning!

Answer 2

So you would have the same slope since the line is parallel. So the slope is m=0.6 and you would write the following in slope intercept form by plugging in 0.6 for m in y=mx+b
So you have
y=0.6x+b and you plug in your point (-3,-5) into the equation and it would be y=-5 and x=-3 so you would say

-5=0.6(-3)+b and you would solve for b

-5=-1.8+b

So b=-5+1.8

b=-3.2
So your equation in slope intercept form would be y=0.6x-3.2

Hope this helps! Merry Christmas!!!