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allsm [11]
2 years ago
10

When a comet is within the inner solar system, its visible tails point __________.

Physics
1 answer:
astraxan [27]2 years ago
6 0

away from the sun

hope it helps...!!!!

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include at least five action items that you and your family will do to conserve energy. PLEASE I NEED HELP! THIS QUESTION IS WOR
wariber [46]
Taking shorter showers, turning off the lights when you aren't in a room, use energy efficient lightbulbs like LED's, use the air conditioning only when you really need it, and use the heat less in the winter.
7 0
3 years ago
Read 2 more answers
A 15kg ball accelerates at a rate of 3m/s/s. What force was required?
hoa [83]

Answer:

<h2>45 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 15 × 3

We have the final answer as

<h3>45 N</h3>

Hope this helps you

3 0
3 years ago
Calculate how far ahead of the drop zone a pilot would have needed to drop humanitarian aid packages if the delivery occurred at
ozzi

Answer:

S = 11488.42 m

Explanation:

Given,

The speed of the jet, v = 0.74 Mach

                                     = 253.82 m/s

The altitude of the jet, h = 10000 m

Since the jet is travelling horizontally, the vertical component of velocity Vy = 0

The equation for a projectile projected from a height h is given by,

                                  S = Vx [Vy + √(Vy² +2gh)] / g

Since Vy = 0

                                   S = Vx √(Vy² +2gh) / g

                                       = 253.82 x √(2 x 9.8 x 10000) / 9.8

                                       = 11488.42 m

Hence, the humanitarian aid package should be delivered ahead of distance, S = 11488.42 m

6 0
3 years ago
PLEASE HELP (100)
morpeh [17]

Answer:

The work done will be W=55.27\: J

Explanation:

The work equation is given by:

W=F\cdot x

Where:

F is the force due to gravity (weight = mg)

x is the length of the ramp (3 m)

Now, the force acting here is the component of weight in the ramp direction, so it will be:

F_{x-direction}=mgsin(28)

Therefore, the work done will be:

W=mgsin(28)*3

W=4*9.81*sin(28)*3

W=55.27\: J

I hope it helps you!

3 0
3 years ago
A car is making a 60 mi trip. It travels the first half of the total distance 30.0 mi at 8.00 mph and the last half of the total
Alja [10]

Answer:

total time =4.583 hour

Explanation:

We have given total distance = 60 mi

It is given that half of the distance traveled by a speed of 8 mph

We know that time\ t=\frac{distance }{speed}=\frac{30}{8}=3.75hour

And second half of the distance traveled by a speed of 36 mph

So time t=\frac{distance }{speed}=\frac{30}{36}=0.833hour

So total time = 3.75 + 0.833 =4.583 hour

3 0
3 years ago
Read 2 more answers
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