The height of the rail on top of the press box where the ball was dropped from is 11.025 m.
The given parameters:
- Time of motion of the ball, t = 1.5 s
- Let the height of the rail = h
<h3>Maximum height of fall;</h3>
- The maximum height through which the ball was dropped from is calculated by applying second equation of motion;
Thus, the height of the rail on top of the press box where the ball was dropped from is 11.025 m.
Learn more about height of projectiles here: brainly.com/question/10008919
Answer:
Wave-cut cliff, sea arch, sea stacks
Explanation:
The effect of a wave erosion is made obvious by the structures formed by the wave action.
The high areas of land adjacent to the incoming wave develop the early features or the formation of wave action, which includes the <em>wave-cut cliff</em>
The continuous undercutting of the cliff by the wave results in the formation of the <em>wave cut platform</em>
The effect of the wave further on a cliff, results in the formation of a sea arch and finally a <em>sea stack</em>
Therefore, the correct sequence is the wave-cut cliff, sea arch, sea stacks
travel through a vacuum at the speed of light. Other waves need a medium; sound waves need molecules that vibrate.
I think it would be E. The higher the object the less wavelength is possible.
Answer:
v=39.05 m/s
Explanation:
Given that
x= 56 cm
F= 158 N
m= 58 g = 0.058 kg
Lets take spring constant = k
At the initial position,before releasing the arrow
F= k x
By putting the values
F= k x
158= 0.56 k
k=282.14 N/m
Now from energy conservation
Lets take final speed of the arrow after releasing
k x²=mv²
282.14 x 0.56² = 0.058 v²
v=39.05 m/s
