Answer:
Displacement: 2.230 km Average velocity: 1.274
Explanation:
Let's represent displacement by the letter S and the displacement in direction 49.7° as A. Displaement is a vector, so we need to decompose all the bird's displacement into their X-Y compoments. Let's go one by one:
- 0.916 km due east is an horizontal direction and cane be seen as direction towards the negative side of X-axis.
- 0.928 km due south is a vertical direction and can be seen as a direction towards the negative side of Y-axis.
- 3.52 km in a direction of 49.7° has components on X and Y axes. It is necessary to break it down using trigonometry,
First of all. We need to sum all the X components and all the Y componets.
∑
⇒ ∑![Sx = [tex]3.52cos(49.7) - 0.916](https://tex.z-dn.net/?f=Sx%20%3D%20%5Btex%5D3.52cos%2849.7%29%20-%200.916)
∑
∑
⇒ ∑
∑
The total displacement is calculated using Pythagoeran therorem:
⇒

With displacement calculated, we can find the average speed as follows:
⇒ 

<span>An alpine glacier can change the topography of a mountainous area through Glacial Erosion and Glacial Deposition. Glaciers are agents of erosion, it can pick up and carry large rocks and sediments. In the process, a deep cavity or hole can form when the glacier plucks a big rock from where it passed. Glaciers have shaped many Mountain Ranges and have created distinct landforms by its erosion process. In Glacial Deposition, as glaciers melt, it deposits all that it carried and a landform is developed.</span>
Answer:
68 db
Explanation:
Since now instead of one two dogs are barking simultaneously close to each other, therefore we take n =2.
Ignoring interference effects, the barking of two dogs result in a higher level of intensity which is given by,
β(db)=10×㏒(2)
=3 db
So, a reasonable estimate for the raised Intensity Level is: 65db+3db = 68db
Answer:
<u><em>The truck was moving 16.5 m/s during the time it took to stop, which was 3 seconds. </em></u>
- <u><em>Initial velocity = 33 m/s</em></u>
- <u><em>Final velocity = 0 m/s</em></u>
- <u><em>Average velocity = (33 + 0) / 2 m/s = 16.5 m/s</em></u>
Explanation:
- <u><em>First, how long does it take the truck to come to a complete stop?</em></u>
- <u><em>( 33 m/s ) / ( 11 m / s^2 ) = 3 seconds</em></u>
- <u><em>Then we can look at the average velocity between when the truck started decelerating and when it came to a complete stop. Because the deceleration is constant (always 11m/s^2) we can use this trick.</em></u>