From someone who has taken physics this is, True
As the scattering angle of the photon increases, the wavelength associated with the photon increases.
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Explanation:</u></h3>
The particle with quantum mechanical property is known as Compton wavelength. The wavelength of a photon increases during collision. When the scattering angle of the photon is 0 degree then the photon's wavelength increases by 0 and when the scattering angle is 180 degree then the wavelength of the photon will become double. This is known as Compton wavelength.
When a photon undergoes collision process, the photo loses its energy and this energy is transferred to the electrons. This causes energy of the photon to decrease and thus the frequency also decreases. Thus, the wavelength of the photon will increase.
Answer:
389.78681 K
Explanation:
= Initial pressure = 55.1 mmHg
= Final pressure = 1 atm = 760 mmHg
= Boiling point
= Initial temperature = 35°C
= Heat of vaporization = 32.1 kJ/mol
From the Clausius-Claperyon equation

The normal boiling point of the substance is 389.78681 K
The net force on q₃ will be 17.51 N. The net force is the algebraic sum of the two forces on the pleading q₃
<h3 /><h3>What is Columb's law?</h3>
The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
The force,by the charge q₁ on the q₃;

The force,by the charge q₂ on the q₃;

The net force is the sum of the two forces;

Hence, the net force on q₃ will be 17.51 N.
To learn more about Columb's law, refer to the link;
brainly.com/question/1616890
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(a)
The work done on the projectile is 9375 joule.
The work on the projectile is calculated as
W=F×d
=1250×7.5
=9375 joule
(b)
The speed of the projectile after 7.5 m is 27.38 m/s
First we need to find out the acceleration of the projectile
F=m×a
1250=25×a
a=50 m/
Now the velocity of the projectile after 7.5 m is calculated as
v^2=u^2+2a×s
v^2=0+2×50*7.5
v=27.38 m/s