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8090 [49]
3 years ago
14

Determine the amount of potential energy of a 5-newton book that is moved to three different shelves on a

Physics
2 answers:
JulijaS [17]3 years ago
4 0
Multiply 5 newton by each height. 1st is 5 joules, 2nd is 7.5, while 3rd is 10 joules.
Elza [17]3 years ago
3 0

Yo sup??

potential energy is given by

U=mgh

mg=5 N

U1=5*1=5 J

U2=5*1.5=7.5 J

U3=5*2=10 J

Hope this helps.

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A flashlight beam makes an angle of 60 degrees with the surface of the water before it enters the water. in the water what angle
alexira [117]
<h3><u>Answer</u>;</h3>

= 22°

<h3><u>Explanation</u>;</h3>
  • According to Snell's law, the ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant. The constant value is called the refractive index of the second medium with respect to the first.
  • Therefore; Sin i/Sin r = η

In this case; Angle of incidence = 90° -60° =30°, angle of refraction =? and η = 1.33

Thus;

Sin 30 / Sin r = 1.33

Sin r = Sin 30°/1.33

       = 0.3759

r = Sin^-1 0.3759

   = 22.08

   <u>≈ 22°</u>

3 0
3 years ago
Explain why we have seasons on earth?
almond37 [142]
It’s because of the tilt of the earth’s axis, it means that w he n the earth leans towards the sun it’s summer, when it leans away from the sun it’s winter and in between the 2 spring and autumn (fall) occur.
5 0
3 years ago
At 600.0 k the rate constant is 6.1× 10–8 s–1. what is the value of the rate constant at 785.0 k?
photoshop1234 [79]
Missing details. Complete text is:"The following reaction has an activation energy of 262 kJ/mol:
C4H8(g) --> 2C2h4(g)
At 600.0 K the rate constant is 6.1× 10–8 s–1. What is the value of the rate constant at 785.0 K?"
To solve the exercise, we can use Arrhenius equation:
\ln( \frac{K_2}{K_1} ) =  \frac{Ea}{R} ( \frac{1}{T_1}- \frac{1}{T_2}  )
where K are the reaction rates, Ea is the activation energy, R=8.314 J/mol*K and T are the temperatures. Using T1=600 K and T2=785 K, and Ea=262 kJ/mol = 262000 J/mol, on the right side of the equation we have
\frac{Ea}{R}( \frac{1}{T_1}- \frac{1}{T_2}  )=12.38
And so
\ln( \frac{K_2}{K_1})=12.38
And using K_1=6.1\cdot 10^{-8} s^{-1} , we find K2:
K_2=K_1 e^{12.38}=0.0145 s^{-1}


5 0
3 years ago
Light is incident perpendicularly on four transparent films of different thickness. The thickness of each film is given in the d
exis [7]

Answer:

1/4 λ film

Explanation:

Let L = total path length then L = 2 t where t is film thickness

There will be a 180 deg phase change at the air-film interface but no

phase change at the film-air interface

L = n * wavelength / 2 where n = 1, 3, 5, 7 etc

(the total path L must be an odd number of 1/2 wavelengths)

Or t = n * wavelength / 4 (the film must be an odd number

of 1/4 wavelengths thick)

1/4 λ film satisfies this condition

Note: Find the missing diagram in the attachment section.

6 0
3 years ago
The tendency of an object to resist change in motion is called
sergeinik [125]

Inertia is the tendency of an object to resist changes in its velocity. An object at rest has zero velocity.

6 0
3 years ago
Read 2 more answers
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