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2 years ago

Which tower is more likely to fall?

Physics

2 answers:

shepuryov [24]2 years ago

6 0

I say B. only because its smaller in width and it has a better chance of falling

Tasya [4]2 years ago

4 0

If there is no difference in angles but one has more width - this one is more likely to fall.

In physics, we use term "center of mass" (geometrical point). 
The displacement of the center of mass from vertical line is higher => higher magnitude of net force => higher chance to fall.

I would say A :)

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An apple is whirled round in a horizontal circle on the end of a string which is tied to the stalk. It is whirled faster and fas

jek_recluse [69]

when the apple moves in a horizontal circle, the tension force in the string provides the necessary centripetal force to move in circle. the tension in the string is given as

T=mv²/r

where T = tension force in the string , m = mass of the apple

v = speed of apple , r = radius of circle.

clearly , tension force depends on the square of the speed. hence greater the speed, greater will be the tension force.

at some point , the speed becomes large enough that it makes the tension force in the string becomes greater than the tensile strength of the string. at that point , the string breaks

6 0

3 years ago

A series of optical telescopes produced an image that has a resolution of about 0.00350 arc second.

Mila [183]

Answer:

The smallest diameter is $D =122 \ m$

Explanation:

From the question we are told that

The resolution of the telescope is $\theta = 0.00350 \ arc \ second$

The wavelength is $\lambda = 1.70 \mu m = 1.70 *10^{-6} \ m$

From the question we are told that

$1 arc \ sec = \frac{1}{3600^o}$

So $0.00350 \ arc \ second = x$

Therefore

$x = 0.00350 * \frac{1}{3600 }$

$x = ( 9.722*10^{-7} )^o$

Now $1^o = \frac{\pi}{180}$

So $(9.722*10^{-7})^o = \theta$

=> $\theta = (9.722*10^{-7}) * \frac{\pi}{180}$

$\theta = 1.69*10^{-8} rad$

The smallest diameter is mathematically represented as

$D = \frac{1.22 \lambda }{\theta }$

substituting values

$D = \frac{1.22 * 1.7 *10^{-6}} {1.69 *10^{-8} }$

$D =122 \ m$

6 0

3 years ago

The kinetic energy K of a moving object varies jointly with its mass m and the square of its velocity v. If an object weighing 4

nata0808 [166]

Answer:

K' = 1777.777 J

Explanation:

Given that

m = 40 kg

v= 15 m/s

K=1000

Given that kinetic energy(K) varies with mass(m) and velocity(v)

K= C(mv²)

Where

C= Constant

m=mass

v=velocity

When

m = 40 kg ,v= 15 m/s ,K=1000

K= C(mv²)

1000 = C( 40 x 15²)

C=0.111111

When m = 40 kg and v= 20 m/s

K' = C(mv²)

K= 0.1111 x (40 x 20²)

K' = 1777.777 J

5 0

3 years ago

Read 2 more answers

A train is accelerating at a rate of 2 km/hr/s. If its initial velocity is 20 km/hr, what is its velocity after 30 seconds?

Aleksandr [31]

"2 km/hr/s" means that in each second, its engines can increase its speed by 2 km/hr.

If it keeps doing that for 30 seconds, its speed has increased by 60 km/hr.

On top of the initial speed of 20 km/hr, that's 80 km/hr at the end of the 30 seconds.

This whole discussion is of speed, not velocity. Surely, in high school physics,
you've learned the difference by now. There's no information in the question that
says anything about the train's direction, and it was wrong to mention velocity in
the question. This whole thing could have been taking place on a curved section
of track. If that were the case, it would have taken a team of ace engineers, cranking
their Curtas, to describe what was happening to the velocity. Better to just stick with
speed.

4 0

3 years ago

A rocket-driven sled running on a straight level track is used to investigate the physiological effects of large accelerations o

Shtirlitz [24]

Answer:

A. a = 814.815 ft/s^2.

B. Distance, S = 320 ft.

Explanation:

Equations of motion

i. vf = vi + a*t

ii. S = vi*t + 1/2*(a*t)

iii. vf^2 = vi^2 + 2a*S

Given:

vi = 0 ft/s

vf = 1000 miles/hr

t = 1.8 s

g = 32 ft/ s2

Converting miles/hr to ft/s,

1 mile = 5280 ft

Also, 1 hr = 60 mins * 60s

= 3600 s

Therefore, 1000 miles/hr * 5280 ft/1 mile * 1 hr/3600 s

= 1466.7 ft/s.

Using the i. Equation of motion,

1466.7 = 0 + a*1.8

a = 814.815 ft/s^2

Comparing a to g,

a = (814.815/32) * g

= 25.46 g

Using the ii. Equation of motion,

S = 1/2 * (814.815) * (1.8)^2

= 1320 ft.

4 0

3 years ago