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ANTONII [103]
3 years ago
9

Which tower is more likely to fall?

Physics
2 answers:
shepuryov [24]3 years ago
6 0
I say B.  only because its smaller in width and it has a better chance of falling 
Tasya [4]3 years ago
4 0
If there is no difference in angles but one has more width - this one is more likely to fall. 

<span>In physics, we use term "center of mass" (geometrical point). </span>
<span>The displacement of the center of mass from vertical line is higher => higher magnitude of net force => higher chance to fall.
</span>
I would say A :)

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How large an expansion gap should be left between steel railroad rails if they may reach a maximum temperature 30.0°C greater th
irina [24]

Answer:

<em>1.2 cm</em>

Explanation:

<u>Thermal Expansion</u>

It's the tendency that materials have to change its size and/or shape under changes of temperature. It can be in one (linear), two (surface) or three (volume) dimensions.

The formula to compute the expansion of a material under a change of temperature from T_o to T_f is given by.

\Delta L=L_o.\alpha .(T_f-T_o)

Where Lo is the initial length and \alpha is the linear temperature expansion coefficient, which value is specific for each material. The data provided in the problem is as follows:

L_o=30\ m,\ T_f-T_o=30^oC,\ \alpha=13\times 10^{-6}\ ^oC^{-1}

Computing the expansion we have

\Delta L=30\times 13\times 10^{-6}(30)=0.0117=1.17\ cm

The expansion gap should be approximately 1.2 cm

6 0
3 years ago
The frequency of the harmonics following a fairly simple pattern, as described in the text. If the frequency of the fundamental
zalisa [80]

Answer:

f2 = 140 Hz

Explanation:

let fundamental frequency is f1 = 70.0 Hz

formula for finding the higher frequency when fundamental frequency is known

fn = n f1          (where f1 is fundamental frequency and n = 1,2,3,4,5...........)

for the second frequency n=2

f2 = 2 × 70.0 Hz

f2 = 140 Hz

6 0
4 years ago
An aluminium bar 600mm long, with diameter 40mm, has a hole drilled in the center of the bar. The hole is 30mm in diameter and i
arsen [322]

Answer:

Explanation:

l = 600mm = 0.6m

d = 40mm = 0.04m

hd = 30mm = 0.03m (diameter of the hole)

hl = 100mm = 0.1m (hole length)

modulus of elasticity for the aluminium = 85GN/m2

compressive load = 180kN

6 0
3 years ago
A ball is thrown straight upward with a speed of 36 m/s. How long does it take to return to its starting point, assuming negligi
svetoff [14.1K]

Answer:

The time taken for the ball to return to the starting point is is 7.4 s

Explanation:

Given;

initial velocity of the ball, u = 36 m/s

the final vellocity at maximum height, v = 0

let time taken for the ball to reach maxmimum height = t

Time taken for the ball to return to the starting point is known as time of flight, calculated as;

t = \frac{v-u}{-g} \\\\T = 2t\\\\T = \frac{2(0-u)}{-g}\\\\T = \frac{-2u}{-g}\\\\ T = \frac{2u}{g}

T = (2 x 36) / 9.8

T = 7.4 s

Therefore, the time taken for the ball to return to the starting point is is 7.4 s

4 0
4 years ago
According to Newton's Brd Law, an object's momentum depends on it's velocity and mass, 4 dog-sled teams
Kryger [21]

Answer:

Team A has the greatest momentum

Explanation:

The momentum of an object is a vector quantity given by

p=mv

where

m is the mass of the object

v is its velocity

In this problem, we have to compare the momenta of the different sleds.

We have:

A) Sled Team A 48 kg moving at 10m/s:

m = 48 kg

v = 10 m/s

p = (48)(10) = 480 kg m/s

B) Sled Team B 14 kg moving at 18m/s

m = 14 kg

v = 18 m/s

p = (14)(18) = 252 kg m/s

C) Sled Team C 28 kg moving at 12m/s

m = 28 kg

v = 12 m/s

p = (28)(12) = 336 kg m/s

D) Sled Team D 22 kg moving at 12m/s

m = 22 kg

v = 12 m/s

p = (22)(12) = 264 kg m/s

So, team A has the greatest momentum.

4 0
3 years ago
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