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Tresset [83]
2 years ago
7

The net of a triangular prism is shown in the diagram. Use the ruler provided to measure the dimensions of the net to the neares

t half centimeter.
Which measurement is closest to the volume of the triangular prism in cubic centimeters?




A.12 cm3


B. 30 CM3


C. 24 CM3


D. 15 CM3​

Mathematics
1 answer:
Bond [772]2 years ago
4 0

Answer:24 cm

Step-by-step explanation:

i took the test

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Answer:

I Know it is B trust me

Step-by-step explanation:

8 0
3 years ago
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Anyone know how to do this
svlad2 [7]

Answer:

The area of the rectangle on the left side is

9cm \:  \times 4cm = 36 {cm}^{2}

The area of the bottom rectangle is

6cm \times 2cm = 12 {cm}^{2}

The total area of the composite figure will be

36 {cm}^{2}  + 12 {cm}^{2}  = 48 {cm}^{2}

Step-by-step explanation:

The area of any given rectangle can be found by multiplying the length of that rectangle by its width. The rectangle on the left side has a length of 9cm but the width is unknown. To find the width, we subtract 6cm from the width of the bottom rectangle: 10cm. And that gives us 4cm.

Therefore, we can now calculate the area to be: length × width = 9cm × 4cm = 36cm²//

The area of the bottom rectangle can be found similarly by multiplying the length: 2cm by the width: 6cm of that rectangle. And the result gives us: 2cm × 6cm = 12cm²//

The total area of the composite figure is calculated by adding the results from the left and bottom rectangles together. And that gives us: 36cm² + 12cm² = 48cm²//

8 0
3 years ago
Need help -5(1+2k)-8(-4+5k)
Nataliya [291]

Answer:

27 - 50k

Simplify

1. Distribute

-5 ( 1 + 2k ) - 8 ( -4 + 5k )

-5 - 10k - 8 ( -4 + 5k )

2. Distribute

-5 - 10k - 8 ( -4 + 5k )

-5 - 10k + 32 - 40k

3. Add the numbers

-5 - 10k + 32 - 40k

27 - 10k - 40k

4. Add the same term to both sides of the equation

27 - 10k - 40k

27 - 50k

6 0
3 years ago
A genetic experiment involving peas yielded one sample of offspring consisting of 420 green peas and 174 yellow peas. Use a 0.01
slavikrds [6]

Answer:

a) z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649  

b) For this case we need to find a critical value that accumulates \alpha/2 of the area on each tail, we know that \alpha=0.01, so then \alpha/2 =0.005, using the normal standard table or excel we see that:

z_{crit}= \pm 2.58

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

Step-by-step explanation:

Data given and notation

n=420+174=594 represent the random sample taken

X=174 represent the number of yellow peas

\hat p=\frac{174}{594}=0.293 estimated proportion of yellow peas

p_o=0.23 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of yellow peas is 0.23:  

Null hypothesis:p=0.23  

Alternative hypothesis:p \neq 0.23  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>3.649)=0.00026  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

b) Critical value

For this case we need to find a critical value that accumulates \alpha/2 of the area on each tail, we know that \alpha=0.01, so then \alpha/2 =0.005, using the normal standard table or excel we see that:

z_{crit}= \pm 2.58

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

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3 years ago
A tiger eats about 6 kilograms of meat per day. how much does it eat in a year (365 days)
Ksivusya [100]
72 kilograms of meat per year.
6×12=72
4 0
3 years ago
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