1: 2.23
2: 0.77
3: 2/3 or 0.6
4: 0.83
5: 1.41
Recall that variation of parameters is used to solve second-order ODEs of the form
<em>y''(t)</em> + <em>p(t)</em> <em>y'(t)</em> + <em>q(t)</em> <em>y(t)</em> = <em>f(t)</em>
so the first thing you need to do is divide both sides of your equation by <em>t</em> :
<em>y''</em> + (2<em>t</em> - 1)/<em>t</em> <em>y'</em> - 2/<em>t</em> <em>y</em> = 7<em>t</em>
<em />
You're looking for a solution of the form

where


and <em>W</em> denotes the Wronskian determinant.
Compute the Wronskian:

Then


The general solution to the ODE is

which simplifies somewhat to

Answer:
$800 = $300 +.05(x), x being the amount that must be sold
Subtract 300 from both sides
$500= .05(x)
Divide by .05
x=$10000
Step-by-step explanation:
Answer:
1,600 dentists were surveyed in total.
Step-by-step explanation:
We can set up a proportion for this problem:

Now we can cross multiply:

1,600 dentists were surveyed in total.
So first, you get the absolute value to one side:

Next, set up two equations; One where the value inside the absolute value lines is positive, and another where it is negative, and solve both for the variable:

Your answers are
8 and -8, or +-8.