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3 years ago

The first triangle is dilated to form the second triangle.

Mathematics

1 answer:

MrRissso [65]3 years ago

8 0

Answer:

Both true

Lelelelellele

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What is the answer? Please help

pav-90 [236]

Answer:

Step-by-step explanation:

g(7) = 7^2 - 3(7) = 49 - 21 = 28

f(28) = 4(28) + 4 = 112 + 4 = 116

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4 years ago

‏ Lainey is looking for a new apartment and her realtor keeps calling her with new listings . The calls only take a few minutes

Anna35 [415]

Answer:

c ) Turn off her phone until she is on a break

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3 years ago

Convert the given radian measure to a degree measure. 5π/3

slega [8]

Answer:

300

Step-by-step explanation:

π radians=180 degree

==> 5π/3 ×π×180

=(5×180)/3

=300

6 0

3 years ago

Tan 3A in terms of tan

Zanzabum

Here's the sum rule for the tangent function:

$\tan(a+b)=\dfrac{\tan(a)+\tan(b)}{1-\tan(a)\tan(b)}$

In the special case a=b, this becomes the double angle formula:

$\tan(a+a)=\tan(2a)=\dfrac{\tan(a)+\tan(a)}{1-\tan(a)\tan(a)}=\dfrac{2\tan(a)}{1-\tan^2(a)}$

In your case, you case use the sum rule once:

$\tan(3a)=\tan(2a+a)=\dfrac{\tan(2a)+\tan(a)}{1-\tan(2a)\tan(a)}$

And use it again, in the special case of the double angle:

$\dfrac{\dfrac{2\tan(a)}{1-\tan^2(a)}+\tan(a)}{1-\dfrac{2\tan(a)}{1-\tan^2(a)}\tan(a)}$

We can obvisouly simplify this expression a lot: let's deal with the numerator and denominator separately: the numerator is

$\dfrac{2\tan(a)}{1-\tan^2(a)}+\tan(a) = \dfrac{2\tan(a)+\tan(a)-\tan^3(a)}{1-\tan^2(a)}$

and the denominator is

$1-\dfrac{2\tan(a)}{1-\tan^2(a)}\tan(a) = \dfrac{1-\tan^2(a)-2\tan^2(a)}{1-\tan^2(a)} = \dfrac{1-3\tan^2(a)}{1-\tan^2(a)}$

So, the fraction is

$\dfrac{2\tan(a)+\tan(a)-\tan^3(a)}{1-\tan^2(a)}\cdot \dfrac{1-\tan^2(a)}{1-3\tan^2(a)} = \dfrac{2\tan(a)+\tan(a)-\tan^3(a)}{1-3\tan^2(a)}$

8 0

4 years ago

F(x)=x^(2)+3x+4 is this quadratic, linear, or neither

goblinko [34]

Quadratic
you’re welcome

8 0

2 years ago