Answer:
<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>
Step-by-step explanation:
Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.
We know that,
So, the <u>speed of Pratap with the current</u> will be: miles/hour
and the <u>speed of Pratap against the current</u> will be: miles/hour.
Suppose, the rate of Pratap in still water is and the rate of current is .
So, the equations will be........
Adding equation (1) and (2) , we will get......
Now, plugging this into equation (1), we will get.....
Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.
The slope-point formula:
We have (0, 3) and (-10, 4)
Substitute:
Answer:
Solutions: (-2. -6), (1, -2), (10, 3), (5, 3)
Step-by-step explanation:
Here is how you solve...
Q= 3a+5ac
take out the common variable.
Q= a(3+5c)
get A by its self so divide each side by (3+5c).
Q/a(3+5c)= a(3+5c)/(3+5c)
Q/a(3+5c)=A
So your answer is A= Q/a(3+5c)
hope that helped.