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3 years ago

If someone can help me figure out #6. Thanks

Mathematics

1 answer:

professor190 [17]3 years ago

3 0

Answer: $(1,-\frac{3}{2})$

Step-by-step explanation:

To find the midpoint, you use the formula $midpoint=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )$ .

The points are (-2,-1) and (4,-2).

$midpoint=(\frac{-2+4}{2} ,\frac{-1+(-2)}{2} )$ [add]

$midpoint=(\frac{2}{2} ,\frac{-3}{2} )$ [divide]

$midpoint=(1 ,\frac{-3}{2} )$

Now, we know the midpoint is $(1,-\frac{3}{2})$ .

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Can someone solve this for me with their explanation please?

Lana71 [14]

First you want to subtract 36

so it looks like this $\sqrt[4] {(4x+164)^3}=64$

Then you want to cancel out the square root 4 by raising that to the 4th power (you must do this to both sides)

${(4x+164)^3}=64^4$ which is equal to ${(4x+164)^3}=16777216$

Then you take the cube root to both sides [tex]\sqrt[3]{(4x+164)^3}=\sqrt[3]{16777216}[tex]

Then you end up with the equation 4x+164=256

Then subtract 164 to both sides

4x=92

then divide 92 by 4

Then you get x=23

7 0

4 years ago

I really need help asap!!

Firdavs [7]

Given:

A figure of a parallelogram.

The vertex angles are $(12b+8)^\circ,(5b+2)^\circ,2a^\circ$ .

To find:

The values of a and b.

Solution:

We know that the pairs of consecutive angles of a parallelogram are supplementary angles. It mean their sum is 180 degrees.

$(12b+8)^\circ+(5b+2)^\circ=180^\circ$ (Supplementary angles)

$(17b+10)^\circ=180^\circ$

$17b+10=180$

Subtract 10 from both sides.

$17b=180-10$

$17b=170$

Divide both sides by 17.

$b=\dfrac{170}{17}$

$b=10$

Now,

$(5b+2)^\circ=(5(10)+2)^\circ$

$(5b+2)^\circ=(50+2)^\circ$

$(5b+2)^\circ=52^\circ$

And,

$(5b+2)^\circ+2a^\circ=180^\circ$ (Supplementary angles)

$52^\circ+2a^\circ=180^\circ$

$2a^\circ=180^\circ-52^\circ$

$2a^\circ=128^\circ$

Divide both sides by 2.

$a^\circ=\dfrac{128^\circ}{2}$

$a^\circ=64^\circ$

$a=64$

Therefore, the value of a is 64 and the value of b is 10.

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Dylan has a roll of wrapping paper that is5 meters long. How many centimeters of wrapping paper does he have.

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3 years ago

Which equation is not a linear function? OA) 2x - 3y = 9 OB) 2x+4y - 12 = 0 OC) y=-3x - 7 OD) 6x + 4y = 8

NeX [460]

OA is not the right one

6 0

3 years ago

Read 2 more answers

I toss an unfair coin 12 times. This coin is 65% likely to show up heads. Calculate the probability of the following.

mars1129 [50]

Answer:

a. 0.0368

b. 0.99992131

c. 0.2039

d. 0.0048

e. 0.6533

Step-by-step explanation:

Let the probability of obtaining a head be p = 65% = 13/20 = 0.65. The probability of not obtaining a head is q = 1 - p = 1 -13/20 = 7/20 = 0.35

Since this is a binomial probability, we use a binomial probability.

a. The probability of obtaining 11 heads is ¹²C₁₁p¹¹q¹ = 12 × (0.65)¹¹(0.35) = 0.0368

b. Probability of 2 or more heads P(x ≥ 2) is

P(x ≥ 2) = 1 - P(x ≤ 1)

Now P(x ≤ 1) = P(0) + P(1)

= ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹

= (0.65)⁰(0.35)¹² + 12(0.65)¹(0.35)¹¹

= 0.000003379 + 0.00007531

= 0.0007869

P(x ≥ 2) = 1 - P(x ≤ 1)

= 1 - 0.00007869

= 0.99992131

c. The probability of obtaining 7 heads is ¹²C₇p⁷q⁵ = 792(0.65)⁷(0.35)⁵ = 0.2039

d. The probability of obtaining 7 heads is ¹²C₉q⁹p³ = 220(0.65)³(0.35)⁹ = 0.0048

e. Probability of 8 heads or less P(x ≤ 8) = ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹ + ¹²C₂p²q¹⁰ + ¹²C₃p³q⁹ + ¹²C₄p⁴q⁸ + ¹²C₅p⁵q⁷ + ¹²C₆p⁶q⁶ + ¹²C₇p⁷q⁵ + ¹²C₈p⁸q⁴

= = ¹²C₀(0.65)⁰(0.35)¹² + ¹²C₁(0.65)¹(0.35)¹¹ + ¹²C₂(0.65)²(0.35)¹⁰ + ¹²C₃(0.65)³(0.35)⁹ + ¹²C₄(0.65)⁴(0.35)⁸ + ¹²C₅(0.65)⁵(0.35)⁷ + ¹²C₆(0.65)⁶(0.35)⁶ + ¹²C₇(0.65)⁷(0.35)⁵ + ¹²C₈(0.65)⁸(0.35)⁴

= 0.000003379 + 0.00007531 + 0.0007692 + 0.004762 + 0.01990 + 0.05912 + 0.1281 + 0.2039 + 0.2367

= 0.6533

3 0

3 years ago