Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.
Find the distance the bottom of the ladder is from the base of the wall.
Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is
0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is
14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.
Ensure that y ou have copied this problem accurately from the original.
5y^2-2x/3x^2y^3
hope you understand its as a fraction.
Answer:
B
Step-by-step explanation:
Divide each coordinate by 2
3/2=1.5
2/2=1
Answer:
z=63°{vertically opposite angle}
now,
z+10x+97=18o°{straight angle}
63+10x+97=180°
10x=180-133
x=<u>2</u><u>0</u>
<u> </u><u> </u><u> </u><u> </u><u> </u>10
x=2
hope it helps.
<u> </u><u> </u><u> </u><u> </u><u> </u>
Answer:
<em>Here</em><em> </em><em>is</em><em> </em><em>your</em><em> </em><em>answer </em><em>.</em><em> </em><em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em>
