Let AB extended intersect DC extended at point E
<span>We now have right triangle BEC with E = 90 degrees </span>
<span>For triangle BEC: </span>
<span>Exterior angle at E = 90 </span>
<span>Exterior angle at C = 148 (given) </span>
<span>Exterior angle of all polygons add up to 360 degrees </span>
<span>Exterior angle at B = 360−148−90 = 122 </span>
<span>So in quadrilateral ABCD </span>
<span>B = 122 </span>
<span>D = 360−44−148−122 = 46</span>
Answer:
your didn't give any proper point ,but i assuming the the question as
the line pass through the point (1,0,-2)
so answer is
(x-1)/a = y/b = (z+2)/c,
where a,b,c are constant
Step-by-step explanation:
-2x(4x² - 5x + 3) Distribute/multiply -2x into (4x² - 5x + 3)
(4x²)(-2x) - (5x)(-2x) + (3)(-2x)
-8x³ + 10x² - 6x
Your answer is the 3rd option
-2.1(4.7+(-7.4))
-2.1(-2.7)
Your answer is...
5.67
Answer:
D
Step-by-step explanation:
