Which segment is not a radius of circle C cq cp rc pq

Mathematics

2 answers:

attashe74 [19]3 years ago

7 0

The answer could be D- pq. It's not from the center of the circle.

zubka84 [21]3 years ago

4 0

Answer:

D. PQ.

Step-by-step explanation:

We have been given a circle. We are asked to find the segment which is not a radius of circle C.

We know that radius of a circle is a segment that connects any point on circle to center of the circle.

Upon looking at our given circle, we can see that CQ, CP and RC are radii of the circle C.

Since PQ is the diameter of our given circle, therefore, segment PQ is not radius of our given circle.

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Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process.

blagie [28]

A.
$5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
5x-4=-2 \times 3x-2 \times 2 \\
5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\
11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\
11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\
x=0$

B.
$3(2x-4)=5x-1 \\
6x-12=5x-1 \\
\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\
11x=11 \\
\boxed{x=11} \Leftarrow \hbox{the second mistake}$

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
$3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\
x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 12 to both sides} \\
x=11$

3 0

3 years ago

5/8 - 4/5 subtract as indicated and express your answer in lowest terms

Nitella [24]

Answer:

-7/40

Step-by-step explanation:

5/8 - 4/5

~Find common denominators

25/40 - 32/40

~Subtract

-7/40