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stiv31 [10]
3 years ago
5

Which segment is not a radius of circle C cq cp rc pq

Mathematics
2 answers:
attashe74 [19]3 years ago
7 0

The answer could be D- pq. It's not from the center of the circle.

zubka84 [21]3 years ago
4 0

Answer:

D. PQ.

Step-by-step explanation:

We have been given a circle. We are asked to find the segment which is not a radius of circle C.

We know that radius of a circle is a segment that connects any point on circle to center of the circle.

Upon looking at our given circle, we can see that CQ, CP and RC are radii of the circle C.

Since PQ is the diameter of our given circle, therefore, segment PQ is not radius of our given circle.

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A prop for the theater club’s play is constructed as a cone topped with a half-sphere. What is the volume of the prop? Round you
prisoha [69]

The volume of the prop is calculated to be 1,875.6 cubic inches.

Step-by-step explanation:

Step 1:

The prop consists of a cone and a half-sphere on top. We will have to calculate the volumes of the cone and the half-sphere separately and then add them to obtain the total volume.

Step 2:

The volume of a cone is determined by multiplying \frac{1}{3} with π, the square of the radius (r²) and height (h). Here we substitute π as 3.14. The radius is 8 inches and the height is 12 inches.

The volume of the cone: \frac{1}{3} \pi r^{2} h = \frac{1}{3} (3.14) (8^{2}) (12)= 803.84 cubic inches.

Step 3:

The area of a half-sphere is half of a full sphere. The volume of a sphere is given by multiplying \frac{4}{3} with π and the cube of the radius (r³).

Here the radius is 8 inches. We take π as 3.14.

The volume of a full sphere= \frac{4}{3} \pi r^{3} = \frac{4}{3} (3.14) (8^{3} ) = 2,143.573 cubic inches.

The volume of the half-sphere= \frac{2,143.573}{2} = 1,071.7865 cubic inches.

Step 4:

The total volume = The volume of the cone + The volume of the half sphere,

The total volume =  803.84+1,071.7865 = 1,875.6265 cubic inches.

Rounding this off, we get the volume of the prop as 1,875.6 cubic inches.

6 0
2 years ago
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