Gallium <u>doesn't</u> have a roman numeral since it's a normal/simple metal.
<span>2 CH3OH + 3 O2 = 2 CO2 + 4 H2O
2 moles CH3OH ---------------- 3 moles O2
1.33 moles CH3OH ----------- ( moles O2)
moles O2 = 1.33 x 3 / 2
moles O2 = 3.99 / 2
= 1.995 moles of O2</span>
Answer:
A. 1.50 M
Explanation:
Concentration is the number of moles of solute dissolved in a volume of 1 L of solution
Mass of LiBr - 97.7 g
Number of moles of LiBr - 97.7 g /87 g/mol = 1.12 mol
Equation for concentration is as follows
Concentration = number of moles / volume of solution in L
Substituting the values
Concentration = 1.12 mol / 0.7500 L
Concentration of LiBr is 1.50 mol/L
Answer:
V=12.6148888506L
Explanation:
using charles law Volume1/Temperature1 = Volume2/Temperature2
13.4L/(17C+273.15C)=V/273.15K
remember gas equations require kelvin not celcius so converting celcius to kelvin is Celcius + 273.15 which is standard temperature conditions
Answer:
The mass of water = 97.28g
The molecular mass of water is
18.01528 g/mol
No of moles of water is 97.28/18.01528 = 5.3998
Approximately 5
Therefore, there are 5 molecules of water in 97.28g of water.