All categories

3 years ago

Does gallium have a roman numeral?

Chemistry

2 answers:

babunello [35]3 years ago

5 0

Gallium <u>doesn't</u> have a roman numeral since it's a normal/simple metal.

Klio2033 [76]3 years ago

4 0

Answer:

Roman numerals are used in the nomenclature of inorganic compounds. They are needed when more than one possible oxidation states are present in the cation; for example, there are Iron(II) and Iron(III). But Gallium has only one oxidation states (+3), so it isn't necessary the use of roman numerals.

You might be interested in

Which of these is a physical property of a tree?

Anit [1.1K]

Is there answer choices?

5 0

3 years ago

Read 2 more answers

Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r

denis23 [38]

Answer :

(1) The frequency of photon is, $3\times 10^{10}Hz$

(2) The energy of a single photon of this radiation is $1.988\times 10^{-23}J/photon$

(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

Explanation : Given,

Wavelength of photon = $1.0cm=0.01m$ (1 m = 100 cm)

(1) Now we have to calculate the frequency of photon.

Formula used :

$\nu=\frac{c}{\lambda}$

where,

$\nu$ = frequency of photon

$\lambda$ = wavelength of photon

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get:

$\nu=\frac{3\times 10^8m/s}{0.01m}$

$\nu=3\times 10^{10}s^{-1}=3\times 10^{10}Hz$ $(1Hz=1s^{-1})$

The frequency of photon is, $3\times 10^{10}Hz$

(2) Now we have to calculate the energy of photon.

Formula used :

$E=h\times \nu$

where,

$\nu$ = frequency of photon

h = Planck's constant = $6.626\times 10^{-34}Js$

Now put all the given values in the above formula, we get:

$E=(6.626\times 10^{-34}Js)\times (3\times 10^{10}s^{-1})$

$E=1.988\times 10^{-23}J/photon$

The energy of a single photon of this radiation is $1.988\times 10^{-23}J/photon$

(3) Now we have to calculate the energy in J/mol.

$E=1.988\times 10^{-23}J/photon$

$E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)$

$E=11.97J/mol$

The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

3 0

3 years ago

Read 2 more answers

Explain how copper conducts electricity?

gladu [14]

Answer:

Copper is a metal made up of copper atoms closely packed together. As a result, the electrons can move freely through the metal. For this reason, they are known as free electrons. They are also known as conduction electrons because they help copper be a good conductor of heat and electricity.

Explanation:

8 0

3 years ago

How many levels of full body protective clothing are there

shutvik [7]

The answer is 4 (four).

Hope this helps!!! :)

5 0

3 years ago

Read 2 more answers

998998998998998998998998998998998998998998998998998

marishachu [46]

Answer: