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postnew [5]
3 years ago
13

State the physical property that makes it possible to separate a solution by distillation. Explain.

Chemistry
1 answer:
KengaRu [80]3 years ago
6 0

Distillation is by definition separation by boiling point. Basically things that have lower boiling points will boil before things that have higher boiling points. so if you go into the temperature range between the two boiling points, one will boil and vaporize and one will remain a liquid (maybe solid).
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a 5.00 l air sample has a pressure of 107 kpa at a temperature of -50.0 C. if the temperature is raised to 102 C and the volume
Murljashka [212]
You have to use the combined gas law (P₁V₁/T₁=P₂V₂/T₂) and solve for P₂ to get P₂=P₁V₁T₂/T₁V₂.

You need to convert all of the temperature values into terms of Kelvin so -50°C turns into 223K and 102°C turns to 375K.  After you make that conversion you can just plug in all of the values into the idea gas law and you should get P₂=228.5kpa.

I hope this helps.  Let me know if anything is unclear.


4 0
3 years ago
Read 2 more answers
If a concentrated solution of acetic acid is 99.5 % HC2 H3 O2 and has a density of 1.05 g/mL, what is the concentration of this
cluponka [151]

Answer:

[CH₃COOH] = 17.4 M

Explanation:

Acetic acid → CH₃COOH

Molar mass → 60 g/mol

99.5% is percent by mass concentration. It means that 99.5 grams of solute are contained in 100g of solution.

Density → 1.05 g/mL. This data is always referred to solution, not solute!.

We determine solution's volume:

1.05 g/mL = 100 g / V → V = 100 g /1.05 g/mL → 95.2 mL

Now we know, that 99.5 g of acetic acid are contained in 95.2 mL

Let's convert to mmoles → 99.5 g / 60 g/mol = 1.66 moles

We convert solution's volume to L → 95.2 mL . 1L / 1000 mL = 0.0952 L

M (mol/L) = 1.66 mol / 0.0952 L = 17.4 M

5 0
4 years ago
What mass in grams of fructose is contained in 325 mL of a 1.5 M fructose solution
STALIN [3.7K]

87.75 g of fructose

Explanation:

molar concentration = number of moles / volume (L)

number of moles = molar concentration × volume

number of moles of fructose = 1.5 × 0.325

number of moles of fructose = 0.4875 moles

number of moles = mass / molar weight

mass =  number of moles × molar weight

mass of fructose = 0.4875 × 180

mass of fructose = 87.75 g

Learn more about:

molar concentration

brainly.com/question/13971392

#learnwithBrainly

3 0
3 years ago
how many moles of ammonium chloride are required for a complete reaction with 420 mol of calcium hydroxide
Oxana [17]

3 KOH + H3PO3 = K3PO4 + 3 H2O  

moles KOH = 26.5 g/56.1 g/mol=0.472  

moles K3PO4 = 0.472/3 =0.157

3 0
3 years ago
Which of the following is an example of potential energy?
maxonik [38]

Answer: the person standing up

Explanation:

the person has the potential to fall or move from position

6 0
4 years ago
Read 2 more answers
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