You have to use the combined gas law (P₁V₁/T₁=P₂V₂/T₂) and solve for P₂ to get P₂=P₁V₁T₂/T₁V₂.
You need to convert all of the temperature values into terms of Kelvin so -50°C turns into 223K and 102°C turns to 375K. After you make that conversion you can just plug in all of the values into the idea gas law and you should get P₂=228.5kpa.
I hope this helps. Let me know if anything is unclear.
Answer:
[CH₃COOH] = 17.4 M
Explanation:
Acetic acid → CH₃COOH
Molar mass → 60 g/mol
99.5% is percent by mass concentration. It means that 99.5 grams of solute are contained in 100g of solution.
Density → 1.05 g/mL. This data is always referred to solution, not solute!.
We determine solution's volume:
1.05 g/mL = 100 g / V → V = 100 g /1.05 g/mL → 95.2 mL
Now we know, that 99.5 g of acetic acid are contained in 95.2 mL
Let's convert to mmoles → 99.5 g / 60 g/mol = 1.66 moles
We convert solution's volume to L → 95.2 mL . 1L / 1000 mL = 0.0952 L
M (mol/L) = 1.66 mol / 0.0952 L = 17.4 M
87.75 g of fructose
Explanation:
molar concentration = number of moles / volume (L)
number of moles = molar concentration × volume
number of moles of fructose = 1.5 × 0.325
number of moles of fructose = 0.4875 moles
number of moles = mass / molar weight
mass = number of moles × molar weight
mass of fructose = 0.4875 × 180
mass of fructose = 87.75 g
Learn more about:
molar concentration
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3 KOH + H3PO3 = K3PO4 + 3 H2O
moles KOH = 26.5 g/56.1 g/mol=0.472
moles K3PO4 = 0.472/3 =0.157
Answer: the person standing up
Explanation:
the person has the potential to fall or move from position