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2 years ago

Can an intermediate appear as a reactant in the first step of a reaction mechanism?.

Chemistry

1 answer:

saveliy_v [14]2 years ago

8 0

Answer:

Explanation:

An intermetiate in a chemical reaction is something that is formed and reused in a reaction.

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An atom from the column 1 can form an iconic compound with another from column 18

Lyrx [107]

The Answer is False

7 0

3 years ago

Which of the following is true for balancing equations?

algol [13]

Answer:

Explanation:

An equation with the equal amount and proportion of atoms of each element on both sides of the reaction is commonly referred to as a balanced chemical equation.

The law of conservation of matter asserts that no observable and empirical change in the amount of matter occurs within a conventional chemical process. As a result, each element in the product would have the same equal amount or numbers of atoms as the reactants.

5 0

3 years ago

draw the lewis structure, including unshared pairs, of the following molecule. carbon has four bonds in the compound. propane (c

SIZIF [17.4K]

There are three carbon and 8 hydrogen present in propane molecule. The Lewis structure of propane is shown as:

Three molecules of such carbon atoms bound to eight molecules with hydrogen atoms make up the organic complex propane molecule.

It is known that carbon has 4 valence electrons and hydrogen has one valence electron. Carbon needs 4 extra electrons to complete its octet hence, it will share its electrons with with 4 hydrogen atom and complete its octet.

Carbon will be formed 4 bond . Three bond with hydrogen and one bond with carbon atom.

To know more about Lewis structure.

brainly.com/question/15837141

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6 0

2 years ago

Why is it important to add coefficients and not change the subscripts when balancing a chemical equation?

Artemon [7]

Because of making the equestion to be more stable and form the best compound according to it's reactant.

5 0

3 years ago

? Answer the question below. Type your response in the space provided. What volume of a 2.5 M stock solution of acetic acid (HC2

Novay_Z [31]

Data:
$M_{concentrated} = 2.5\:mol$
$V_{concentrated} = ?$
$M_{dilute} = 0.50\:mol$
$V_{dilute} = 100\:mL\to0.100\:L$

Formula: Dilution Calculations

 $M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}$

Solving:


$M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}$
$2.5 * V_{concentrated} = 0.50 * 0.100$
$2.5V_{concentrated} = 0.05$
$V_{concentrated} = \frac{0.05}{2.5}$
$\boxed{\boxed{V_{concentrated} = 0.02\:L\:or\:20\:mL}} \end{array}}\qquad\quad\checkmark$

3 0

3 years ago