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2 years ago

WILL GIVE BRAINLIEST find the y-intercept of the parabo;a y= -33/4 x^2 + 4

Mathematics

1 answer:

valentinak56 [21]2 years ago

6 0

Answer:

The y-intercept is (0, 4)

Since the y-intercept marks the point where x =0, all that you have to do is substitute 0 in for x in the parabola's equation.

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There are 5 chemistry, 6 physics, and 7 math teachers in a school. if 3 teachers are selected randomly, find the probability tha

mrs_skeptik [129]

77.2%

To find the probably and at least on you must find the probability of none and subtract from one.

The probability of none can be found like so:

(5+6 over 5+6+7)^3 = .228

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Hope this helps!

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2 years ago

Which property is demonstrated below? (b·c)d=b(c·d) A. associative property B. distributive property C. commutative property D.

Snezhnost [94]

Answer:

associative

Step-by-step explanation:

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3 years ago

Read 2 more answers

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gladu [14]

Answer: D. 2,800

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2 years ago

Ali and Heather drew floor models of their living room Ellie model represented 20 feet by 15feet Heather model represented 18fee

alina1380 [7]

Ellie: 20*15=300
Heather: 18*18= 324
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4 0

2 years ago

Which of the following are solutions to the equation below?

scoundrel [369]

Answer:

The correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Step-by-step explanation:

Given the expression

$x^2+10x+25=8$

Subtract 25 from both sides

$x^2+10x+25-25=8-25$

Simplify

$x^2+10x=-17$

Add 25 or 5² to both sides

$x^2+10x+5^2=8$

$x^2+10x+5^2=\left(x+5\right)^2$

so the expression becomes

$\left(x+5\right)^2=8$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x+5=\sqrt{8}$

Subtract 5 from both sides

$x+5-5=2\sqrt{2}-5$

$x=2\sqrt{2}-5$

solve

$x+5=-\sqrt{8}$

Subtract 5 from both sides

$x+5-5=-2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Therefore, the solution to the equation

$x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5$

Hence, the correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

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3 years ago