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Alekssandra [29.7K]
2 years ago
14

176.98 round to the nearest cent

Mathematics
1 answer:
Olegator [25]2 years ago
7 0

Answer:

See answer(s) below

Step-by-step explanation:

$ 176.98   to nearest cent is  $ 176.98

176.98 cents rounded to the nearest cent is 177 cents

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Someone please help!!!!<br> 6+2/3x&gt;12-1/3x
attashe74 [19]

Answer:

the answer is x>6

Step-by-step explanation:

hope dis right

5 0
3 years ago
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Which equation is the inverse of 5 y + 4 = (x + 3) squared + one-half?
8_murik_8 [283]

The inverse of the given function is y = √5x + 7/2 - 3

<h3>Inverse of a function</h3>

Given the function expressed below;

5y + 4 = (x+3)² +1/2

5y = (x+3)² - 7/2

y = 1/5(x+3)² - 7/10

Replace y as x

x = 1/5(y+3)² - 7/10

Make y the subject of the formula

5x = (y+3)²- 7/2

(y+3)² = 5x + 7/2

y+3 = √5x + 7/2

y = √5x + 7/2 - 3

Hence the inverse of the given function is y = √5x + 7/2 - 3

learn more on inverse of a function here: brainly.com/question/3831584

#SPJ1

4 0
2 years ago
Write the square of (2x+1/x)
pentagon [3]

Answer:

((2 x^2 + 1)^2)/(x^2)

Step-by-step explanation:

Simplify the following:

(2 x + 1/x)^2

Hint: | Put the fractions in 2 x + 1/x over a common denominator.

Put each term in 2 x + 1/x over the common denominator x: 2 x + 1/x = (2 x^2)/x + 1/x:

((2 x^2)/x + 1/x)^2

Hint: | Combine (2 x^2)/x + 1/x into a single fraction.

(2 x^2)/x + 1/x = (2 x^2 + 1)/x:

((2 x^2 + 1)/x)^2

Hint: | Distribute exponents over quotients in ((2 x^2 + 1)/x)^2.

Multiply each exponent in (2 x^2 + 1)/x by 2:

Answer: ((2 x^2 + 1)^2)/(x^2)

6 0
3 years ago
If the sumof two numbers,n and m,is rational,which statement is true?
Nataly_w [17]

Option B:

Both n and m must be rational.

Solution:

Given information:

Sum of two numbers, n and m are rational.

<u>To find which statements are true:</u>

Option A: Both n and m may be rational but do not have to be.

It is not true because n and m given is rational.

It have to be rational.

Option B: Both n and m must be rational.

Yes, n and m must be rational then only the sum of numbers are rational.

It is true.

Option C: Both n and m must be irrational.

Sum of irrationals will be sometimes irrational and sometimes can't add.

So it is not true.

Option D: One number is rational and the other is irrational.

Rational and irrational cannot be add.

So it is not true.

Option B is true.

Both n and m must be rational.

5 0
3 years ago
A? B? C? D?..................................................
zhenek [66]

Answer:

A.

Step-by-step explanation:

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5 0
2 years ago
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