Answer:
A. AC, CB
Step-by-step explanation:
The answer you have selected is correct because a line segment is a part of a line that is bounded by two distinct end points, and contains every point on the line that is between its endpoints. Thus the answer A is correct!
Hope this helps
All the love, Ya boi Fraser :)
Answer:
3x-8y-16 = 0
Step-by-step explanation:
The answer is A 1/2 sorry if I’m wrong if not A its c
<u>Given</u><u> </u><u>Information</u><u> </u><u>:</u><u>-</u>
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- A polygon with 10 sides ( Decagon )
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<u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u>-</u>
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- The value of one of the exterior angles
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<u>Formula</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>
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![\qquad \diamond \: \underline{ \boxed{ \pink{ \sf Exterior ~angle = \dfrac {360^\circ}{no. ~of~sides}}}} \: \star](https://tex.z-dn.net/?f=%20%5Cqquad%20%5Cdiamond%20%5C%3A%20%20%5Cunderline%7B%20%5Cboxed%7B%20%5Cpink%7B%20%5Csf%20Exterior%20~angle%20%3D%20%5Cdfrac%20%7B360%5E%5Ccirc%7D%7Bno.%20~of~sides%7D%7D%7D%7D%20%5C%3A%20%20%5Cstar)
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<u>Solution</u><u> </u><u>:</u><u>-</u>
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Putting the given values, we get,
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![\sf \dashrightarrow Exterior ~angle = \dfrac{360 ^\circ}{10} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \frac{36 \cancel{0}^\circ}{ \cancel{10}} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \underline{ \boxed{ \frak{ \red{36^\circ}}}} \: \star \\ \\](https://tex.z-dn.net/?f=%5Csf%20%5Cdashrightarrow%20Exterior%20~angle%20%3D%20%20%5Cdfrac%7B360%20%20%5E%5Ccirc%7D%7B10%7D%20%5C%3A%20%20%5C%3A%20%20%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%5Csf%20%5Cdashrightarrow%20Exterior%20~angle%20%3D%20%20%5Cfrac%7B36%20%5Ccancel%7B0%7D%5E%5Ccirc%7D%7B%20%5Ccancel%7B10%7D%7D%20%5C%3A%20%20%5C%3A%20%20%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%5Csf%20%5Cdashrightarrow%20Exterior%20~angle%20%3D%20%20%5Cunderline%7B%20%5Cboxed%7B%20%5Cfrak%7B%20%5Cred%7B36%5E%5Ccirc%7D%7D%7D%7D%20%5C%3A%20%5Cstar%20%5C%5C%20%20%5C%5C%20)
Thus, the value of the exterior angles of a Decagon is 36°.
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![\underline{ \rule{227pt}{2pt}} \\ \\](https://tex.z-dn.net/?f=%20%5Cunderline%7B%20%5Crule%7B227pt%7D%7B2pt%7D%7D%20%5C%5C%20%20%5C%5C%20)
Answer:
14 miles.
Step-by-step explanation:
Let the distance traveled from home to destination = x miles.
Speed while going to friend's house = 35 miles per hour.
Speed while coming back = 40 miles per hour.
Total Time taken for the journey = 45 minutes = 0.75 hours.
Let the time taken while going to friend's house = y hours.
Therefore, the time taken while going to friend's house = (0.75 - y) hours.
To find x and y, model the speeds of both the journeys.
Speed while going to friend's house = Distance/Time.
35 = x/y.
x = 35y (Equation 1).
Speed while coming back = Distance/Time.
40 = x/(0.75 - y).
x = 40(0.75 - y) (Equation 2).
Since x = x, therefore:
35y = 30 - 40y.
75y = 30.
y = 30/75.
y = 0.4 hours.
Put y = 0.4 hours in Equation 1:
x = 35y.
x = 35(0.4).
x = 14.
Therefore, the distance between my friend's house and my house is 14 miles!!!