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olga_2 [115]
3 years ago
14

Non-examples of air pressure

Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
8 0
No pressure







Ahhhhhh (filling character req)
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1) When chromium chloride, CrCl2, is dissolved in water, the temperature of the water decreases. a) Is the heat of solution exot
Mandarinka [93]

Answer:

Explanation:  It has been given that the temperature of the water decreases when chromium chloride is dissolved in water. Thus fall in the temperature explains the fact that the bond energies of the reactants have more energy rather than the products.

a) Thus the heat of the solution is endothermic in nature as more energy is needed to break the reactant molecules.

b) The combined ionic bond strength of CrCl2 and inter molecular forces between water molecules must be stronger than the attractive forces between the  water molecules and chromium and chloride ions as the reaction is endothermic in nature thus more energy would be required to break the bonds between the reactants hence making them more stronger.

3 0
3 years ago
One mole of an ideal gas, for which CV,m = 3/2R, initially at 298 K and 1.00 × 105 Pa undergoes a reversible adiabatic compressi
oksian1 [2.3K]

Answer:

  • final temperature (T2) = 748.66 K
  • ΔU = w = 5620.26 J
  • ΔH = 9367.047 J
  • q = 0

Explanation:

ideal gas:

  • PV = RTn

reversible adiabatic compression:

  • δU = δq + δw = CvδT

∴ q = 0

∴ w = - PδV

⇒ δU = δw

⇒ CvδT = - PδV

ideal gas:

⇒ PδV + VδP = RδT

⇒ PδV = RδT - VδP = - CvδT

⇒ RδT - RTn/PδP = - CvδT

⇒ (R + Cv,m)∫δT/T = R∫δP/P

⇒ [(R + Cv,m)/R] Ln (T2/T1) = Ln (P2/P1) = Ln (1 E6/1 E5) = 2.303

∴ (R + Cv,m)/R = (R + (3/2)R)/R = 5/2R/R = 2.5

⇒ Ln(T2/T1) = 2.303 / 2.5 = 0.9212

⇒ T2/T1 = 2.512

∴ T1 = 298 K

⇒ T2 = (298 K)×(2.512)

⇒ T2 = 748.66 K

⇒ ΔU = Cv,mΔT

⇒ ΔU = (3/2)R(748.66 - 298)

∴ R = 8.314 J/K.mol

⇒ ΔU = 5620.26 J

⇒ w = 5620.26 J

  • H = U + nRT

⇒ ΔH = ΔU + nRΔT

⇒ ΔH = 5620.26 J + (1 mol)(8.314 J/K.mol)(450.66 K)

⇒ ΔH = 5620.26 J + 3746.787 J

⇒ ΔH = 9367.047 J

8 0
3 years ago
Enter your answer in the provided box. an aqueous solution containing 10 g of an optically pure substance was diluted to 500 ml
sladkih [1.3K]

Answer:

[α] = -77.5° / \frac{\textup{dm-g}}{\textup{mL}}

Explanation:

Given;

Mass of optically pure substance in the solution = 10 g

Volume of water = 500 mL

Length of the polarimeter, l = 20 cm = 20 × 0.1 dm = 2 dm

measured rotation = - 3.10°

Now,

The specific rotation ( [α] ) is given as:

[α] = \frac{\alpha}{c\times l}

here,

α is the measured rotation = -3.10°

c is the concentration

or

c = \frac{\textup{Mass of optically pure substance in the solution}}{\textup{Volume of water}}

or

c =  \frac{10}{500}

or

c = 0.02 g/mL

on substituting the values, we get

[α] = \frac{-3.10^o}{0.02\times2}

or

[α] = -77.5° / \frac{\textup{dm-g}}{\textup{mL}}

7 0
3 years ago
How many atoms are there in 5.20 mil of hafnium. Please help due in 1hr
Levart [38]
In 5.70 mol of Hafnium there are 34,326
8 0
2 years ago
Most full scuba tanks have a pressure of between 1,800 p.s.i. and 3,000 p.s.i. (pounds per square inch). Approximately 70 to 85
ArbitrLikvidat [17]

Answer: The Diver's air tank is filled with oxygen gas.

The filling of air tank while keeping in water can be explained in reference to the Charles' Law.

Charles' Law: It states that the volume of the ideal gas is directly proportional to the absolute temperature at constant pressure.

                        V\propto T    (at constant Pressure)

The Scuba tank contains cold water and is present at high pressure. The gas which is put in the tank will be compact and would not expand. As the temperature is low inside the tank, hence by using Charles' Law, the volume will also decrease inside the tank.

When the air tank is filled, it is always kept in a tub of water because the pressure is high and hence, more oxygen gas can be filled inside the air tank.


8 0
3 years ago
Read 2 more answers
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