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boyakko [2]
2 years ago
5

Which of these is an example of a physical change?

Chemistry
1 answer:
vladimir2022 [97]2 years ago
6 0

Answer:

Their isn't your examples but I will give you mine

Freezing, Evaporation and so on.

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Answer:

2KBr + MgF₂ –> 2KF + MgBr₂

The coefficients are: 2, 1, 2, 1

Explanation:

KBr + MgF₂ –> KF + MgBr₂

The above equation can be balance as illustrated below:

KBr + MgF₂ –> KF + MgBr₂

There are 2 atoms of F on the left side and 1 atom on the right. It can be balance by writing 2 before KF as shown below:

KBr + MgF₂ –> 2KF + MgBr₂

There 2 atoms of K on the right side and 1 atom on the left side. It can be balance by writing 2 before KBr as shown below:

2KBr + MgF₂ –> 2KF + MgBr₂

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Which of the following has the smallest radius? <br> A. O^2- <br> B. F^- <br> C. Li^- <br> D. Be^2+
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Answer : The correct option is, (D) Be^{2+}

Explanation :

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For ions, the effective nuclear charge changes than the neutral atom.

There are two types of ions:

Cations: They are formed when an atom looses its valence electrons. They are positive ions.

Anions: They are formed when an atom gain electrons in its outermost shell. They are negative ions.

For positive ions, the removal of electron increases the nuclear charge for an outermost electron because the outermost electrons are more strongly attracted by the nucleus. Thus, the effective nuclear charge increases for cations.

From this we conclude that, the size of the cation is smaller than their neutral atom because it has less number of electrons while its nuclear charge remains the same. So, the nucleus attracts the electron more towards itself and leads to the decrease in size.

For negative ions, the addition of electron decreases the nuclear charge for an outermost electron because the outermost electrons are less strongly attracted by the nucleus. Thus, the effective nuclear charge decreases for anions.

From this we conclude that, the size of the anion is greater than their neutral atom because it has more number of electrons while its nuclear charge remains the same. So, the nucleus attracts the electron less towards itself and leads to the increase in size.

Thus, the increasing order of radius of ions will be:

Be^{2+}

Hence, the smallest radius of ion is, Be^{2+}

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3 years ago
Why is it important to use the net force instead of the applied force when calculating the acceleration?
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