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hammer [34]
2 years ago
8

The graph of linear function g passes through the points (-7, -4) and (7, 6)

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
7 0

Answer:

<h3>C. The slope is 5/7, and the y-intercept is 1.</h3>

Step-by-step explanation:

You must solve the slope-intercept form with the graph of the linear function g passing through the points.

Use the slope-intercept form.

\underline{\text{SLOPE-INTERCEPT FORM:}}

\Longrightarrow: \sf{y=mx+b}

  • M= slope
  • B= y-intercept.

Use the slope formula.

\underline{\text{SLOPE:}}

\Longrightarrow \sf{\dfrac{y_2-y_1}{x_2-x_1} }

(-7,-4) and (7,6)

  • y2=6
  • y1=(-4)
  • x2=7
  • x1=(-7)

\sf{\dfrac{6-\left(-4\right)}{7-\left(-7\right)}}

Solve.

\sf{\dfrac{6-\left(-4\right)}{7-\left(-7\right)}=\sf{\dfrac{10}{14}=\dfrac{10\div2}{14\div2}=\dfrac{5}{7}   }}

  • <u>Therefore, the slope is 5/7 and y-intercept is 1.</u>
  • <u>The correct answer is C. "The slope is 5/7, and the y-intercept is 1."</u>

I hope this helps. Let me know if you have any questions.

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Answer:

A) Q(x) = (x + 3)² + 5, and the vertex is (-3, 5)

B) R(x) = (x - 3)² + 2, and the vertex is (3, 2)

C) S(x) = (x - 1)² - 5, and the vertex is (1, -5)

Step-by-step explanation:

The given function is P(x) = (x + 3)² + 2

The given function is a parabolic function in vertex form, f(x) = a·(x - h)² + k, and vertex, (h, k)

By comparison, the vertex of the function P(x) = (x + 3)² + 2 is (-3, 2)

A) A function f(x) translated α units UP gives

f(x) (translated α units UP) → f(x) + α

A translation of the function 3 units UP is given by adding 3 to the given function as follows;

Q(x) = P(x) + 3

∴ Q(x) = (x + 3)² + 2 + 3 = (x + 3)² + 5

Q(x) = (x + 3)² + 5, and the vertex by comparison to f(x) = a·(x - h)² + k, and vertex, (h, k) is (-3, 5)

B) A function f(x) translated <em>b</em> units RIGHT gives;

f(x) translated <em>b</em> units right → f(x - b)

∴ P(x) = (x + 3)² + 2 translated 6 units RIGHT gives;

P(x) = (x + 3)² + 2 (translated 6 units RIGHT) → R(x) = (x + 3 - 6)² + 2 = (x - 3)² + 2

R(x) = (x - 3)² + 2, and the vertex by comparison is (3, 2)

C) A function translated α units DOWN and <em>b</em> units RIGHT is given as follows;

f(x) \ translated \ by\  \dbinom{b}{a} \rightarrow f(x - b) - a

Therefore, the given function, P(x) = (x + 3)² + 2, translated 7 units DOWN and 4 units RIGHT gives;

P(x) = (x + 3)^2 + 5 \ translated \ by\  \dbinom{4}{-7} \rightarrow P(x - 4) - 7 = S(x)

S(x) = P(x - 4) - 7 = (x + 3 - 4)² + 2 - 7 = (x - 1)² - 5

P(x) = (x + 3)^2 + 5 \ translated \ by\  \dbinom{4}{-7} \rightarrow (x - 1)^2 - 5= S(x)

S(x) = (x - 1)² - 5, and the vertex by comparison is (1, -5)

7 0
3 years ago
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