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bonufazy [111]
3 years ago
5

Given b = 4 and c = -5, evaluate b 2 - c 2. 41 -2 -9

Mathematics
1 answer:
LekaFEV [45]3 years ago
6 0
I hope this helps you

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Luden [163]
37.68 is the correct answer
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2 years ago
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This figure is made up of a rectangle and parallelogram.
patriot [66]

calculate length of the sides of the rectangle and multiply then do the same with the parallelogram

 Total area is 51 square units

7 0
3 years ago
The shaded portion of the grid below represents the portion of a granola bar remaining.
Nady [450]

Answer:

A. 1%

B. 80%

C. 0.8, 8/10

Step-by-step explanation:

A. There are 100 blocks so each block is 1/100 which is 1%

B. As you can see, there are 80 blocks shaded so that would be 80/100 which is 80%

C. You can represent a percent as a decimal or a fraction

Hope this helped!

8 0
3 years ago
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Which is true about the degree of the sum and difference of the polynomials 3x5y – 2x3y4 – 7xy3 and –8x5y 2x3y4 xy3?.
ki77a [65]

The degree of the sum and difference of the polynomials are 6 and 7 respectively.

given polynomials are:

3x^5-2x^3y^4-7xy^3

-8x^5y+2x^3y^4+xy^3

the sum of polynomials = -5x^5y-6xy^3

the difference of polynomials = 11x^5y-4x^3y^4-8xy^3

<h3>what is the degree of a polynomial?</h3>

A polynomial's degree is the highest or the greatest power of a variable in a polynomial equation.

degree of sum = monomial with highest power = 5+1=6

degree of difference = monomial with highest power = 3+4 = 7

therefore, the degree of the sum and difference of the polynomials are 6 and 7 respectively.

to get more about polynomials refer to:

brainly.com/question/1600696

4 0
2 years ago
Below are three different hypothesis tests about population proportions. For each test, use StatKey and the information given to
Ilia_Sergeevich [38]

Answer:

1a) p-hat=0.38

1b) P=0.08

1c) The null hypothesis is not rejected

2a) p-hat=0.64

2b) P=0.0027

2c) The null hypothesis is rejected

3a) p-hat=0.55

3b) P=0.153

3c) The null hypothesis is not rejected

Step-by-step explanation:

(1) H0: p = 0.3 vs Ha: p ≠ 0.3. In their survey, they had a count of 38 using a sample size n=100.

1a) The p-hat is p-hat=38/100=0.38.

1b) The standard deviation is

\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.3*0.7}{100}}=0.046

The sample size is n=100.

The z-value is:

z=\frac{\hat{p}-p}{\sigma}=\frac{0.38-0.3}{0.046}=\frac{0.08}{0.046}= 1.74

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=1.74 is P=0.08.

1c) The null hypothesis is not rejected.

(2) H0: p = 0.7 vs Ha: p ≠ 0.7. In their survey, they had a count of 320 using a sample size n=500.

2a) The p-hat is p-hat=320/500=0.64.

2b) The standard deviation is

\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.7*0.3}{500}}=0.02

The sample size is n=500.

The z-value is:

z=\frac{\hat{p}-p}{\sigma}=\frac{0.64-0.7}{0.02}=\frac{-0.06}{0.02}=-3

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=3 is P=0.0027.

2c) The null hypothesis is rejected.

(3) H0: p = 0.6 vs Ha: p < 0.6. In their survey, they had a count of 110 using a sample size n=200.

2a) The p-hat is p-hat=110/200=0.55.

2b) The standard deviation is

\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.6*0.4}{200}}=0.035

The sample size is n=200.

The z-value is:

z=\frac{\hat{p}-p}{\sigma}=\frac{0.55-0.6}{0.035}=\frac{-0.05}{0.035}=-1.43

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=1.43 is P=0.153.

2c) The null hypothesis is not rejected.

8 0
3 years ago
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