Perimeter of rectangle is 8x and Area is 3x^2 + 2x -1..
Lets try to solve out the problem,
Length = 3x-1
Width = x+1
Perimeter = 2(l+b)
Area = l*b
Perimeter= 2 (3x-1 + x+1)
P= 8x
Area = (3x-1) (x+1)
=> 3x(x+1) -1 (x+1)
=> 3x^2 + 3x -x -1
=> 3x^2 + 2x -1.
Hence Perimeter of rectangle is 8x and Area is 3x^2 + 2x -1..
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Answer:
1. 208 in^2
Step-by-step explanation:
1. We can break the shape up into a rectangle in the middle and 2 triangles on either side of said rectangle.
The dimensions of the rectangle are 8 in by 20 in, and we only know one leg of the triangle as well as the hypotenuse.
If we know one leg and the hypotenuse we can use the pythagorean theormed to sovle for the other side and get 6 in.
So we have
(8 * 20) + 2((1/2)(6)(8))
160 + 48
208 in^2
Answer:
-19
Step-by-step explanation:
P=$24038.60 has to be invested to have $45000 after 19 years
It is hard to comprehend your question. As far as I understand:
f(x,y) = e^(-x)
Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.
That is all I understood. It would be easier to understand with a picture or some kind of visual aid.
Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.
Now evaluate,
which evaluates to, 5/6 if I did the math correct. Correct me if I am wrong.
Now integrate this w.r.t. y:
So,
