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2 years ago

הום חמווובוביות חוב פובוס 2 M 150 K к 9 12 180 090

Mathematics

1 answer:

netineya [11]2 years ago

5 0

9514 1404 393

Answer:

a = 6

Step-by-step explanation:

A triangle inscribed in a semicircle is always a right triangle, so ...

15a° = 90°

a = 90/15

a = 6

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Simplify the expression:<br> 4(2 + 5q) = 1

JulijaS [17]

Answer:

Step-by-step explanation:

4(2+5q) = 8 + 20q

8 + 20q = 1

20q = -7

q = -7/20

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2 years ago

A right triangle has a leg of 12 cm and a hypotenuse of 19 cm.

Yakvenalex [24]

Answer:

14.7 cm

Step-by-step explanation:

Using Pythagoras Theorem,

The length of the other leg

$= \sqrt{ {19}^{2} - {12}^{2} }$

$= \sqrt{217}$

$= 14.730919...$

= 14.7 cm (rounded to the nearest tenth)

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3 years ago

Sweet noticed the ratio of long boards to short boards was 1:4. If there were 35 surfboards at the beach , how many were short b

andre [41]

So the ratio to longboard to short board is 1:4, the total of that ratio is 5. 35 ÷ 5 = 7. now we're going to take those ratios and multiply 1 × 7 = 7 and 4 × 7 = 28. Your final answer is B. to confirm your answer add 28 + 7.

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2 years ago

When Isaac commutes to work, the amount of time it takes him to arrive is normally distributed with a mean of 44 minutes and a s

mario62 [17]

Answer:

[34,54]

Step-by-step explanation:

-The empirical rule states that the 95% of the sampled observations will fall within two standard deviations of the mean for a normally distributed population.

Where:

68% is the first standard deviation
95% is the second standard deviation about the mean
99.7% is the 3rd standard deviation about the mean.

-Therefore. the middle 95% interval is calculated as:

$CI=\mu+2\sigma\\\\=44\pm 2(5)\\\\=44\pm 10\\\\=[34,54]$

Hence, the interval is [34,54]

5 0

2 years ago

When commercial aircraft are inspected, wing cracks are reported as nonexistent, detectable, or critical. The history of a parti

Kamila [148]

Answer:

0.226

Step-by-step explanation:

Given that:

No wing crack (x) = 70%

Detectable wing crack (y) = 25%

Critical wing crack (z) = 5%

Number of samples (n) = 5

Probability that atleast a plane has critical crack:

1 - p(no critical crack)

Using the multinomial distribution calculator :

P(5,0,0) + p(4,1,0) + p(3,2, 0) + p(2,3,0) + p(1,4,0) + p(0,5,0)

From the calculator :

P(5,0,0) + p(4,1,0) + p(3,2, 0) + p(2,3,0) + p(1,4,0) + p(0,5,0) = 0.7741

1 - 0.7741 = 0.2259

= 0.226

7 0

2 years ago