A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
Answer:
Step-by-step explanation:
2 because if you divide 14 by 7 to isolate the variable you get 2
Answer:
F = -44. I have attached the work too
The answer is: $ 0.0538888888888889 / in.______________________________Round to: $0.05388 per inch.________________________________Explanation:________________________________Note the exact conversion: 1 feet (ft) = 12 inch (in.) .
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<span>$ 0.0538888888888889 / in. .
→ Round to: $ 0.05388 / in. __________________________________</span>