Very simple.
Let's say you have an equation.
f(x) = x^2
You are asked to find the value for y when x equals 1.
The new equation is: f(1) = (1)^2
f(1) = 1
When x = 1, y = 1.
The same concept is applied here.
In the graph, where does x equal 0?
It equals zero at the origin.
Is there any y-value associated with 0?
Yes, there is.
Y equals five when x equals 0.
So
h(0) = 5
Plug in x = 7. Then use the order of operations (PEMDAS) to simplify
y = 11 - 5*x
y = 11 - 5*7 .... x has been replaced with 7 (since x = 7 is given)
y = 11 - 35
y = -24
Answer:
(3w - 7)(3w + 7)
Step-by-step explanation:
The expression is a difference of squares and factors in general as
a² - b² = (a - b)(a + b)
Thus
9w² - 49
= (3w)² - 7²
= (3w - 7)(3w + 7)
Answer: -1.5/6 = -1/4; -1.7/9 = -17/90
Step-by-step explanation: Yeah, I'm not exactly sure what the problem is asking for, but this how I interpreted it. Use the LCD of the fractions -1.5/6 and -1.7/9 to find equivalent fractions with integer numerators and denominators.
For me, LCD doesn't help with solving the problem that much.
But anyways, the first fraction, -1.5, can be turned in an integer if you multiply the entire fraction by 2. So the result would be -3/12. You can simplify this to -1/4.
The second fraction, when multiplied by 10 yields -17/90. 17 is a prime number and is not a factor of 90, thus the equivalent fraction of -1.7/9 is 17/90.
Hope this helped.