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3 years ago

Simplify the expression 14+8x2

Mathematics

1 answer:

cluponka [151]3 years ago

6 0

using BIDMAS or BODMAS it would be 14+(8*2) which is 14+16 = 30

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In ABC segment DC bisects /_C and divides AB into segment AD and BD. CD = 6 units and AC = 8.5, then which statement would

eduard

Answer:

ABC=BCD wtdf

Step-by-step explanation:

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3 years ago

May B. Luckie tosses a dart at the April calendar on the wall. What are the ODDS that the dart hits a date that is a prime numbe

meriva

Answer:

The ODDS that the dart hits a date that is a prime number are 1:1

Step-by-step explanation:

Odds:

An odd is writen as:

Number of desired outcomes: Number of undesired outcomes.

In this question:

April has 30 days, 15 of which are prime numbers and 15 of which are odd numbers.

So the odds are:

15:15

Simplifying by 15

1:1

The ODDS that the dart hits a date that is a prime number are 1:1

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3 years ago

Company A offers a starting salary of $28000 with a raise of $3000 each year, Company B offers a starting salary of $36000 with

telo118 [61]

We can conclude that both will intersect at a certain angle, depending on this algorithm I created.

28000 + 3000x = 36000 + 2000x

The f(x) intercept for g(x) is = 9 and -9

If you square this by light, the arithmetic of 9x+5x=21s(x)

Thus we can simply and get 11 years.

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3 years ago

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A recent study at UGA (March 5, 2008) suggests that students with cell phones may take more risks than students that do not have

Ira Lisetskai [31]

Answer:

(a) -2.8

b) (1) Reject H0: p = 0.50 in favor of HA: p < 0.50; there is sufficient evidence to conclude that less than half of all UGA female students who, if they had a cell phone, would be willing to walk somewhere after dark that they would normally not go.

Step-by-step explanation:

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

H0: p = 0.50

This means that:

$\mu = 0.5, \sigma = \sqrt{0.5*0.5} = 0.5$

In a random sample of 305 UGA female students, 128 responded that, if they had a cell phone, they would be willing to walk somewhere after dark that they would normally not go.

This means that $n = 305, X = \frac{128}{305} = 0.4197$

a) Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.4197 - 0.5}{\frac{0.5}{\sqrt{305}}}$

$z = -2.8$

Pvalue:

We are testing the hypothesis that the proportion is less than 0.5, which means that the pvalue of the test is the pvalue of z = -2.81.

Looking at the z-table, z = -2.8 has a pvalue of 0.0026

(b) What is the correct conclusion for this hypothesis test at the 0.05 level of significance?

0.0026 < 0.05, which means that we reject the null hypothesis, that the proportion is 0.5, and accept the alternate hypothesis, that the proportion is less than 0.5, option (1).

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3 years ago

A school debate team has 4 girls and 6 boys. A total of 3 of the team members will be chosen to participate in the district deba

Varvara68 [4.7K]

The probability that 1 girl and 2 boys will be selected is given by:
$P(1\ boy,\ 2\ girls)=\frac{4C1\times6C2}{10C3}=\frac{1}{2}$
The correct answer choice is B. 1/2.

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3 years ago

Read 2 more answers