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tatyana61 [14]
2 years ago
10

For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10

g+-1/10-4/5g+1 1/10. Is his final expression equivalent to the initial expression? Show how you know. If the tow expressions are not equivalent, find Tyson’s mistake and correct it
Mathematics
1 answer:
professor190 [17]2 years ago
3 0

The true statements are:

  • Tyson's expression is not equivalent to the original expression
  • The equivalent expression is:\frac{1}{2}g- \frac 1{5}

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}

Collect like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10}  -\frac{1}{10}

Evaluate the like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}

Tyler's equivalent expression is given as:

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}

Collect like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}

Evaluate the like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

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Natalija [7]
To find the number halfway between 60 and 75, we use the following formula:

(X + Y)/2 = Halfway Between

When we enter 60 and 75 into our formula, we get:

(60 + 75)/2 = 67.5

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3 0
3 years ago
Factor the expression below 36a2-25b2 which binomial is factor of the expression
Serhud [2]

Answer: (6a + 5b) • (6a - 5b)

 

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "b2"   was replaced by   "b^2".  1 more similar replacement(s).

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (36 • (a2)) -  52b2

Step  2  :

Equation at the end of step  2  :

 (22•32a2) -  52b2

Step  3  :

Trying to factor as a Difference of Squares :

3.1      Factoring:  36a2-25b2

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  36  is the square of  6

Check : 25 is the square of 5

Check :  a2  is the square of  a1

Check :  b2  is the square of  b1

Factorization is :       (6a + 5b)  •  (6a - 5b)

Final result :

 (6a + 5b) • (6a - 5b)

brainly would epic!

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<span>thus arranging from greatest to least:6km, 60m, 600 cm or 6000mm</span>

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Answer:

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