To find the number halfway between 60 and 75, we use the following formula:
(X + Y)/2 = Halfway Between
When we enter 60 and 75 into our formula, we get:
(60 + 75)/2 = 67.5
Thus, the number halfway between 60 and 75 is 67.5.
Answer: (6a + 5b) • (6a - 5b)
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "b2" was replaced by "b^2". 1 more similar replacement(s).
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(36 • (a2)) - 52b2
Step 2 :
Equation at the end of step 2 :
(22•32a2) - 52b2
Step 3 :
Trying to factor as a Difference of Squares :
3.1 Factoring: 36a2-25b2
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 36 is the square of 6
Check : 25 is the square of 5
Check : a2 is the square of a1
Check : b2 is the square of b1
Factorization is : (6a + 5b) • (6a - 5b)
Final result :
(6a + 5b) • (6a - 5b)
brainly would epic!
6 kilometers is the greatest,but arranging from greatest to least: 6km, 60m, 600 cm or 6000mm
60 meters = 60 meters * 1km/1000 meters = 0.06 km600 centimeters = 600 cm * 1m/100cm * 1km/1000m = 0.006 km6000 millimeters = 6000mm * 1m/1000mm * 1km/1000m = 0.006km
<span>thus arranging from greatest to least:6km, 60m, 600 cm or 6000mm</span>
Answer:
Since -14 is added in each term
Therefore,in 68 th term will be 68×-14 +(-19)
As the 1 st term is -19
68 th term= -952+(-19)
68 th term= -971