For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10
1 answer:
The true statements are:
- Tyson's expression is not equivalent to the original expression
- The equivalent expression is:
Equivalent expressions are expressions that have equal values
The original expression is given as:
Collect like terms
Evaluate the like terms
Tyler's equivalent expression is given as:
Collect like terms
Evaluate the like terms
The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.
Hence, Tyson's expression is not equivalent to the original expression
Read more about equivalent expressions at:
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Answer:
We have the system of equations:
y=1/3x+5
y=2/3x+5
To solve it graphically, we need to graph both lines and see in which point the lines intersect.
You can see the graph below, and you can see that the lines intersect in the point (0, 5)
Now, we can also solve this analytically.
We can use the fact that for the solution, we need y = y.
Then we can write:
(1/3)*x + 5 = (2/3)*x + 5
First, we can subtract 5 in both equations to get:
(1/3)*x = (2/3)*x
This only has a solution when x = 0.
Replacing x = 0 in one of the equations, we get:
y = (1/3)*0 + 5 = 5
Then the solution is x = 0, and y = 5, as we already could see in the graph.
