Answer:
y =
x + 7
Step-by-step explanation:
the equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b ) a point on the line
y - 8 = -
(x + 5) ← is in point- slope form
with m = - ![\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D)
given a line with slope m then the slope of a line perpendicular to it is
= -
= -
= ![\frac{3}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D)
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept ) , then
y =
x + c ← is the partial equation
to find c substitute (- 6, - 2 ) into the partial equation
- 2 = - 9 + c ⇒ c = - 2 + 9 = 7
y =
x + 7 ← equation of line K
Answer:
The mean of W is 55 ounces.
The standard deviation of W is 4.33 ounces.
Step-by-step explanation:
Let X: weight of a red delicious apple, and B: the weight of the box and packing material.
The distribution that will represent W: the total weight of the packaged 5 randomly selected apples will be also normally distributed.
Applying the property of the mean:
, the mean of W will be:
![\mu_W=E(W)=E(5X+B)=5E(X)+E(B)=5*9+10=45+10=55](https://tex.z-dn.net/?f=%5Cmu_W%3DE%28W%29%3DE%285X%2BB%29%3D5E%28X%29%2BE%28B%29%3D5%2A9%2B10%3D45%2B10%3D55)
Applying the property of the variance:
, the variance of W will be:
![\sigma^2_W=V(W)=V(5X+B)=5^2V(X)+V(B)=25*0.75+0=18.75](https://tex.z-dn.net/?f=%5Csigma%5E2_W%3DV%28W%29%3DV%285X%2BB%29%3D5%5E2V%28X%29%2BV%28B%29%3D25%2A0.75%2B0%3D18.75)
The mean standard deviation of W will be the squared root of V(W):
![\sigma_W=\sqrt{V(W)}=\sqrt{18.75}=4.33](https://tex.z-dn.net/?f=%5Csigma_W%3D%5Csqrt%7BV%28W%29%7D%3D%5Csqrt%7B18.75%7D%3D4.33)
The mean of W is 55 ounces.
The standard deviation of W is 4.33 ounces.
I believe it's the 3rd one
Is it like this?
y=-4+8
y=4
Is this what you need?
Answer:
63
Step-by-step explanation:
Just subtract 26 from 89.