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Nataly [62]
2 years ago
7

If a solution has a concentration of 12 M when the volume is 150 mL. What is the new concentration if you increase the volume to

600 mL? (1
sig fig)
M
Chemistry
1 answer:
swat322 years ago
6 0

Answer:

The idea with diluting a solution is that the number of moles of solute will remain constant after the initial solution is diluted. The only ...

Explanation:

hope it helps you

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sulfur combines with hydrogen to form hydrogen sulfide H2 S by single covalent bond, while it form with potassium by ionic bond​
Alex

Answer: Ions may be defined as the element that contains either positive or negative charge over them. Two types of ions are cations and anions. The outermost electrons are involved in the formation of ions.

The atomic number of sulfur is 16. Its outermost electronic configuration is K=2, L= 8, M= 6. The sulfur requres two more electrons to complete its orbit and accquire -2 charge.

Explanation:

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3 years ago
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An indicator helps us to see the _____ during a titration experiment by causing a color change
Liula [17]

Answer:

Point of neutralization.

Explanation:

Indicators are used in titration experiments to show when the solution's pH is changing. For instance, a common indicator, phenolphthalein, turns pink in basic solutions, while it remains colorless in acidic solutions. The solution would turn a very light shade of pink when the pH reached above 7.

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3 years ago
OMG HELP!!!! I SUCK AT SCIENCE
Maksim231197 [3]
Organism are made up of organic molecules consisting of carbon, hydrogen, oxygen, nitrogen, sulfur, and phosphorus.

The answer is B.
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2 years ago
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Three-quarters of the elements are..
Dennis_Churaev [7]

Answer:

metals

Explanation:

Approximately three-quarters of all known chemical elements are metals. The most abundant varieties in the Earth's crust are aluminum,... Gold (Au), chemical element, a dense lustrous yellow precious metal of Group 11 (Ib), Period 6, of the periodic table.

8 0
3 years ago
Please need help..
bogdanovich [222]

Answer:

1. The empirical formula => C₆H₁₀OS₂

2. Molecular formula => C₃₆H₆₀O₆S₁₂

Explanation:

1. Determination of the empirical formula.

Carbon (C) = 2.96 g

Hydrogen (H) = 0.414 g

Oxygen (O) = 0.675 g

Sulphur (S) = 2.96 g

Divide by their molar mass

C = 2.96 / 12 = 0.247

H = 0.414 / 1 = 0.414

O = 0.675 / 16 = 0.042

S = 2.96 / 32 = 0.0925

Divide by the smallest

C = 0.247 / 0.042 = 6

H = 0.414 / 0.042 = 10

O = 0.042 / 0.042 = 1

S = 0.0925 /0.042 = 2

Therefore, the empirical formula is

C₆H₁₀OS₂

2. Determination of the molecular formula.

Molar mass of compound = 972 g/mol

Empirical formula => C₆H₁₀OS₂

Molecular formula =>?

Molecular formula = [C₆H₁₀OS₂]ₙ

Molecular formula = molar mass of compound

Thus,

[C₆H₁₀OS₂]ₙ = 972

[(12×6) + (10×1) + 16 + (32×2)]n = 972

[72 + 10 + 16 + 64]n = 32

162n = 972

Divide both side by 162

n = 972 / 162

n = 6

Molecular formula = [C₆H₁₀OS₂]ₙ

Molecular formula = [C₆H₁₀OS₂]₆

Molecular formula = C₃₆H₆₀O₆S₁₂

3 0
3 years ago
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