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kondaur [170]
3 years ago
8

Assuming that compound a has only c, h, and one n atoms, determine the molecular formula, and then draw a possible structure if

compound a has ir absorption at 1620-1680 cm-1 but not at 3010-3090 cm-1

Chemistry
1 answer:
White raven [17]3 years ago
5 0
The peak at 1620-1680 cm⁻¹ is characteristic absorption peak of C=C stretching while peak at 3010-3100 cm⁻¹ is characteristic absorption peak of C-H streching in which C is sp² hybridized.

It means that the structure contains carbon double bond carbon but there is no H attached to sp² hybridized carbon.

I have drawn one structure which follows the scenario. And molecular formula of Molecule is C₆H₉N.

Result:
           According to given information the best suggested compound has formula C₆H₉N with structure shown below,

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SOMEONE PLEASE HELP ME WITH THIS QUESTION!!!!!!!!!!!!
Advocard [28]

Answer:

KOH

Explanation:

Chemical reaction:

2K + 2H₂O →  2KOH + H₂

Element ratio of K.

K = 1

Because only potassium is present.

Element ratio of H₂O.

2 : 1

in water ratio of element is 2 : 1 because two hydrogen and one oxygen atom present.

Element ratio of KOH

1 : 1 : 1

in KOH elemental ratio is 1 : 1 : 1 because one potassium one hydrogen and one oxygen atom are present.

Element ratio of H₂.

2

Just two atoms of hydrogen are present.

8 0
3 years ago
Solid Silicon can be reacted with Nitrogen gas at a high temperature to form silicon nitride (Si3N4).
slamgirl [31]
Solid Silicon can be reacted with Nitrogen gas at a high temperature to form silicon nitride (Si3N4).
1.20 moles of Silicon are added to 1.00 moles of Nitrogen gas.
(5 Points) Balance the equation and indicate the phases.

Si (___) + N2 (___) → Si3N4 (___)

(5 Points) What is the limiting reactant? You must show your work.
4 0
3 years ago
Which of the following aqueous solutions will have the lowest freezing point? a. 0.75 m (NH4)3PO4 b. 1.0 m CaSO4 c. 1.0 m LiCl d
Nataly [62]

Answer: a. 0.75m (NH4)3PO4 will have the lowest freezing point .

Explanation: Freezing point decreases as the concentration of the solute substance increases. Assuming the same solvent for all of them, for instance water.

∆T= i.Kf.b

∆T= freezing point depression

i= vant Hoff factor

Kf= molality

Assuming water to be the solvent for all Kf=1.86°C/M

VANT HOFF FACTORS :

For (NH4)3PO4

This has 3 ionic bonding and 1 covalent bonding making it 4 bond

Therefore i=4

For CaSO4

This has 1 metallic bond and 1 covalent bond making it 2 bond.

Therefore i=2

For LiCl

This has 1 metallic bond and 1 non metallic bond making it 2 bond.

Therefore i=2

For CH3OH

This has only 1 covalent bond.

Therefore i=1

MOLALITY:

(NH4)3PO4 = 0.75M

CaSO4= 1.0M

LiCl= 1.0M

CH3OH= 1.5M

FREEZING POINT DEPRESSION:

For (NH4)3PO4

∆T= 4×0.75×1.86=5.58°C

For CaSO4

∆T= 2×1.0×1.86=3.72°C

For LiCl

∆T = 2×1.0×1.86= 3.72°C

For CH3OH

∆T= 1×1.5×1.86=2.79°C

REMEMBER THE HIGHER THE FREEZING POINT DEPRESSION THE LOWER THE FREEZING POINT.

FREEZING POINT DEPRESSION IS THE CHANGE IN THE FREEZING POINT PROPORTIONAL TO THE AMOUNT OF SOLUTE ADDED THE THE SOLUTION.

THEREFORE THE ONE WITH THE LOWEST FREEZING POINT IS (NH4)3PO4

4 0
4 years ago
How many moles of water, H2O, contain 2.0×1022 molecules of water?
zimovet [89]
<span>Should be 3.2*10^-2 moles</span>
6 0
3 years ago
The elements found in Group 2A, from top to bottom, include beryllium, magnesium, calcium, strontium, and barium. Which of these
Sedaia [141]
<span>The correct answer is Beryllium. They all belong to atoms that have low electronegativity, and as you go down the group the farther away you are the lower it gets. This means that they are not good at bonding with and attracting pairs of electrons. Berryllium has an electronegativity of 1.5, which is low compared to Fluorine, the highest one that has 4.</span>
7 0
3 years ago
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